java - 通过对数组进行排序来创建排名列表

Question

我有两个数组，其中一个数组表示名称集合，另一个数组描述其关联的标记。我想按升序对数组内的标记进行排序，然后再对与标记相关的相应名称进行排序。

我的目标是创建一个排名列表。我正在使用处理来执行此操作

float sum = 0;

String [] name = {"A", "B", "C", "D","E"};
float [] mark = {12, 2, 4, 6, 23};

void setup() {

  size(600, 600);
  smooth();
}

void draw() {
  background(225);
  fill(0);
  println(name.length); 
  for (int i =0; i<name.length; i++) {
    text(name[i] + ":"+ mark[i], 100, 100+i*50);
  }
}

/////// i wanted to sort it as E:23,    A:12,    D:6,     C:4,     B:2

如果有人能帮助我解决这个问题，那就太好了。 :)

提前非常感谢，优素福

Answer 1

您可以创建一个实现Comparable的数据持有者类。我认为您还可以使用 Map，例如 hashMap。

这里是一个数据持有者类示例:

import java.util.Collections;

ArrayList <Data> d = new ArrayList<Data>();

void setup() {
  size(600, 600);

  d.add(new Data("A", 12));
  d.add(new Data("B", 2));
  d.add(new Data("C", 4));
  d.add(new Data("D", 6));
  d.add(new Data("E", 23));



  println("before sorting:\n" + d);

  //used reverseOrder as it goes decrescent, but you could just reverse
  //the "natural" order in the class it self. Exchange -1 and 1 in compareTo()
  // and use Collections.sort(d); here
  Collections.sort(d, Collections.reverseOrder());

  println("after sorting:\n" + d);
}


/////// i wanted to sort it as E:23,    A:12,    D:6,     C:4,     B:2


class Data implements Comparable {
  String name;
  int mark;

  Data(String _n, int _m) {
    name = _n;
    mark = _m;
  }

  // this sets the 'natural' order of Data
  @Override
    int compareTo(Object o) {
    Data other = (Data) o;

    if (other.mark > mark) {
      return -1;
    } else if (other.mark < mark) {
      return 1;
    }
    return 0;
  }


  // this to get a nice looking output in console...
  @Override
    String toString() {
    return name + ":" + nf(mark, 2);
  }
}