java - 仅使用 Jersey 和 Java 创建一个简单的 html 服务器

Question

不知道为什么我在寻找使用 Jersey 制作简单网络服务器的方法时遇到如此大的麻烦。

public class AnotherJerseyHttpServer {

    public static void main(String[] args) throws IOException {
        System.out.println("Starting Crunchify's Embedded Jersey HTTPServer...\n");
        HttpServer webServer = createHttpServer();
        webServer.start();
        System.out.println(String.format("\nJersey Application Server started with WADL available at " + "%sapplication.wadl\n", getURI()));
        System.out.println("Started Crunchify's Embedded Jersey HTTPServer Successfully !!!");
    }

    public static HttpServer createHttpServer() throws IOException {
        ResourceConfig rc = new PackagesResourceConfig("com.daford");
        // This tutorial required and then enable below line: http://crunfy.me/1DZIui5
        //rc.getContainerResponseFilters().add(CrunchifyCORSFilter.class);
        return HttpServerFactory.create(getURI(), rc);
    }

    private static URI getURI() {
        return UriBuilder.fromUri("http://" + sHostname() + "/").port(4444).build();
    }

    private static String sHostname() {
        String hostName = "localhost";
        try {
            hostName = InetAddress.getLocalHost().getCanonicalHostName();
        } catch (UnknownHostException e) {
            e.printStackTrace();
        }
        return hostName;
    }
}

并且

@Path("api")
public class RestAPI {


    @GET
    @Produces(MediaType.TEXT_PLAIN)
    public String get() {
        return "this works";
    }
}

我可以做http://localhost:4444/api并得到“这有效”。现在我如何允许基于传入 URL 的 html 文件？我获得了各种 MediaType/mimi 信息，但我无法在网上找到任何信息来告诉我如何根据传入的 URL 返回文件。

Answer 1

假设您需要返回的文件打包在您的WAR文件中，您可以尝试以下解决方案:

使用Google Guava

@Path("/{fileName: .+}")
@Produces(MediaType.TEXT_HTML)
public class HtmlResource {

    @GET
    public Response getPage(@PathParam("fileName") String fileName) throws IOException {
        URL url = Resources.getResource(fileName);
        return Response.ok(Resources.toString(url, Charsets.UTF_8)).build();
    }
}

使用纯 Java 代码

@Path("/{fileName: .+}")
@Produces(MediaType.TEXT_HTML)
public class HtmlResource {

    @GET
    public Response getPage(@PathParam("fileName") String fileName) throws IOException {
        InputStream stream = HtmlResource.class.getClassLoader()
                                 .getResourceAsStream(fileName);
        String responseContent = read(stream);
        return Response.ok(responseContent).build();
    }

    private String read(InputStream stream) throws IOException {
        try (BufferedReader buffer = new BufferedReader(new InputStreamReader(
                                             stream, StandardCharsets.UTF_8))) {
            return buffer.lines().collect(Collectors.joining("\n"));
        }
    }
}

例如，fileName 可以是 assets/index.html。