java - 为什么我的代码使用提供的集合输出可笑的数字？我正在尝试 String.format

Question

我使用这些数字:5,4,3.5,10,20,40,80,93.33,-1。它可以处理只有 5 个数字的简单数字，例如:5,4,3,2,1。到底是怎么回事？如果这是问题的话，我正在尝试使用 String.format 来缩短数字。你们是否注意到我的代码中有什么我可以做不同的事情来避免这种情况。这是提供的设置的输出:

The minimum is -1.0, the maximum is 2.147483647E9, and the average is 2.38609322E8
-238609317.00
-238609318.00
1908874325.00
-238609312.00
-238609302.00
-238609282.00
-238609242.00
-238609229.00
-238609323.00    

期望的输出

最小值为 3.5，最大值为 93.33，平均值为 31.978749999999998

得分 5.0 与平均值相比为 -26.978749999999998

得分 4.0 与平均值相比为 -27.978749999999998

得分 3.5 与平均值的比值是 -28.478749999999998

得分 10.0 与平均值相比为 -21.978749999999998

得分 20.0 与平均值相比为 -11.978749999999998

分数 40.0 是平均分 8.021250000000002

分数 80.0 与平均值的比值是 48.02125

分数 93.33 与平均值 61.35125 的差距

public static void main(String[] args)
{
  int count = 0;
  int arrayLength;
  double min = 99999;
  double max = 0;
  double average;
  double sum = 0;
  JOptionPane.showMessageDialog(null, "This program will display the average as well as each numbers distance from the average");
  // need to put loop here.
  arrayLength = IO.readInt("How many numbers will you be entering?");
  if (arrayLength <= 0 || arrayLength > 100)
  {
     JOptionPane.showMessageDialog(null, "Nothing entered, program will close.");
     System.exit(0);
  }
  double[] array = new double[arrayLength];
  for (int i = 0; i <arrayLength; i++)
  {
     array[i] = IO.readInt("Enter number: " + (i+1));
     count++;  
  } 
  for (int i = 0; i <arrayLength; i++)
  {
     sum = (array[i] + sum);
     if (array[i] <= min)
     {
        min = array[i];
     }
     if (array[i] > max)
     {
        max = array[i];
     }
  }
  average = (sum / arrayLength);
  System.out.println("The minimum is " + min + ", the maximum is " + max + ", and the average is " + average);
  double[] array2 = new double[arrayLength];
  for (int i = 0; i <arrayLength; i++)
  {
     array2[i] = (array[i] - average);
  }
  for (int i = 0; i <arrayLength; i++)
  {
     System.out.println(String.format("%.2f", array2[i]));
  }

}

Answer 1

我不知道当你执行 IO.readInt 并将其放入 double 时会发生什么，但它不可能是你想要的......