Grails openid 插件 2.0.0 RC1 : getting "No such property: User exception"

Question

已安装 openid plugin 2.0.0 RC1 到我的 grails 应用程序，但我越来越没有这样的属性:用户异常。有人可以建议应该做什么吗？

| Error 2013-10-28 00:11:55,169 [http-bio-8080-exec-6] ERROR errors.GrailsExceptionResolver  - MissingPropertyException occurred when processing request: [POST] /Test/login/openIdCreateAccount - parameters:
username: valid_gmail@gmail.com
password2: ***
password: ***
No such property: User for class: grails.plugin.springsecurity.openid.OpenIdRegisterCommand. Stacktrace follows:
Message: No such property: User for class: grails.plugin.springsecurity.openid.OpenIdRegisterCommand
   Line | Method
->> 265 | doCall   in grails.plugin.springsecurity.openid.OpenIdRegisterCommand$__clinit__closure1_closure2
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - 
|   195 | doFilter in grails.plugin.cache.web.filter.PageFragmentCachingFilter
|    63 | doFilter in grails.plugin.cache.web.filter.AbstractFilter
|    53 | doFilter in grails.plugin.springsecurity.web.filter.GrailsAnonymousAuthenticationFilter
|    49 | doFilter in grails.plugin.springsecurity.web.authentication.RequestHolderAuthenticationFilter
|    82 | doFilter in grails.plugin.springsecurity.web.authentication.logout.MutableLogoutFilter
|   895 | runTask  in java.util.concurrent.ThreadPoolExecutor$Worker
|   918 | run      in     ''
^   695 | run . .  in java.lang.Thread

Answer 1

这个bug在RC2中没有修复，我前两天安装了它，遇到了同样的问题。实际上，OpenIdController 中有 4 个错误。我将在下面的建议答案中提及 user2576874 修复的这些错误的详细信息及其解决方案:

1:第 267 行，该类在 OpenIdRegistrationCommand 的静态闭包中引用 grailsApplication bean。这里给出的解决方案是将grailsApplication替换为:grails.util.Holders.getGrailsApplication()

2:第286行，当我们尝试在OpenId登录回调后注册用户时，正则表达式失败。这是一个更简单的 regEx 条件:

(!password.matches('^.*[a-zA-Z].*$') ||
!password.matches('^.*[0-9].*$') ||
!password.matches('^.*[!@#$%^&].*$')))

3:第183行，字段名错误:usernamePropertyName。正确的字段名称是 usernamePropName，如第 49 行所述。

4:运行代码会抛出 NullPointerException，因为 Role 类没有被定义为类型。解决方案是将类类型添加到与 User 和 UserRole 定义相同的变量 Role 中。在 OpenIdConroller 的第 255 行之后添加了以下代码:

角色 = grailsApplication.getClassForName(conf.authority.className)

谢谢