java - 使用 BreakIterator 跳过非字母字符

Question

我的目标是使用 BreakIterator 将“<,Bold,>”转换为“< Bold>”(“<”和“B”之间没有空格)

说字符串“这是一个测试。”是我的输入

public static List<String> getWords(String text) {
    List<String> words = new ArrayList<String>();
    BreakIterator breakIterator = BreakIterator.getWordInstance();
    breakIterator.setText(text);
    int lastIndex = breakIterator.first();
    while (BreakIterator.DONE != lastIndex) {
        int firstIndex = lastIndex;
        lastIndex = breakIterator.next();
        if (lastIndex != BreakIterator.DONE) {
            String t = text.substring(firstIndex, lastIndex);
            words.add(t);
        }
    }
    return words;
}

getWords(String) 返回 <,Bold,>, ,This, ,is, ,a, ,test。

我已经尝试过:

            String t = text.substring(firstIndex, lastIndex);
            if (t != "<" || t != ">" || t != "/" || t != ">") System.out.println("Char Not Skipped " + t); else System.out.println("Char Skipped" + t);
            //if (text.charAt (firstIndex - 1) == '<') t = "<" + t;
            //if (text.charAt (lastIndex + 1) == '>') t += ">";
            //if (text.charAt (lastIndex + 1) == '/' && text.charAt (lastIndex + 2) == '>') t += "/>";
            //System.out.println(t);
            words.add(t);

返回的只是 Char Not Skipped。

Answer 1

我不确定我是否正确地回答了您的问题。

如果要删除全部,在你的字符串中你可以轻松地做到:

    String s = "<,Bold,>, ,This, ,is, ,a, ,test";
    String newString = s.replace(",", "");
    System.out.println(newString);

输出如下:

This is a test

如果您只想删除<,和,>你可以使用:

   String s = "<,Bold,>, ,This, ,is, ,a, ,test";   
   String newString =  (s.replace("<,", "<")).replace(",>", ">");
   System.out.println(newString);

输出为

<Bold>, ,This, ,is, ,a, ,test