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java - hibernate,无法保存多对一关系

转载 作者:行者123 更新时间:2023-12-01 10:44:58 25 4
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我一直在研究@ManyToOne hibernate注释的教程,但不完全理解一些东西。为了简单解释,这里是一段代码:

@Entity
@Table
public class Student {

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;
@Column
private String name;
@OneToMany(mappedBy = "student", fetch = FetchType.LAZY)
private Set<Book> bookList;
// getters, setters...
}

@Entity
@Table(name = "book")
public class Book {

@Id
@Column(name = "ID")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;
@Column(name = "NAME", unique = true, nullable = false, length = 100)
private String name;
@Column(name = "DESCRIPTION", unique = true, nullable = false, length = 100)
private String description;
@ManyToOne(fetch = FetchType.LAZY, optional = true)
@JoinTable(name = "CATALOG", joinColumns = @JoinColumn(name = "ID_BOOK"), inverseJoinColumns = @JoinColumn(name = "ID_STUDENT"))
private Student student;
// getters, setters...
}

并且,当我执行这两个类时:

Session session = factory.getCurrentSession();
//start
System.out.println("start!");
Book book = new Book();
book.setName("bulk");
book.setDescription("hulk");
//book set
session.beginTransaction();
session.save(book);
//book saved
Student stud = new Student();
stud.setName("Mark");
//stud set
Set<Book> books = new HashSet<>();
book.setStudent(stud);
books.add(book);
//book add to list
stud.setBookList(books);
//list added to stud
session.save(stud);

session.getTransaction().commit();

结果显然是:

start!
Hibernate: insert into book (DESCRIPTION, NAME) values (?, ?)
Hibernate: insert into Student (name) values (?)
Hibernate: insert into CATALOG (ID_STUDENT, ID_BOOK) values (?, ?)
end

现在,当我对这两个类做同样的事情时(在我看来,显然,否则它会起作用):

@Entity
@Table(name = "client",
uniqueConstraints = {
@UniqueConstraint(columnNames = {"client_id"})})
public class Client {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "client_id", nullable = false, unique = true, length = 11)
private int id;
@Column(name = "client_name", length = 60, nullable = true)
private String name;
@Column(name = "client_comment", length = 60, nullable = true)
private String comment;
@Column(name = "client_activated", nullable = true)
private boolean activated;

@OneToMany(mappedBy = "client", fetch = FetchType.LAZY)
Set<AdditionalProperty> propertiesList;

// start of class properties

@Entity
@Table(name = "user_properties",
uniqueConstraints = {
@UniqueConstraint(columnNames = {"property_id"})})
public class AdditionalProperty {

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "property_id")
private int id;
@Column(name = "property_name", length = 60, nullable = true)
private String name;
@Column(name = "property_type", length = 60, nullable = true)
private String propertyType;
//@ManyToOne(cascade = CascadeType.ALL)
//@JoinColumn(name = "property_to_client")
//@ManyToOne(fetch = FetchType.LAZY,optional=true)
//@JoinTable(name = "ref_client_to_property", joinColumns = @JoinColumn(name = "ref_property_id"), inverseJoinColumns = @JoinColumn(name = "ref_client_id"))
@ManyToOne(fetch = FetchType.LAZY, optional = true)
@JoinTable(name = "ref_client_to_prop", joinColumns = @JoinColumn(name = "id_prop"), inverseJoinColumns = @JoinColumn(name = "id_client"))
private Client client;

当我执行这段代码时:

AdditionalProperty prop = new AdditionalProperty();
prop.setName("testf2");
prop.setPropertyType("testt2");
AdditionalProperty prop2 = new AdditionalProperty();
prop2.setName("wat2");
prop2.setPropertyType("wat");
//props set
new HibernateDAOAdditionalProperty().create(prop);
new HibernateDAOAdditionalProperty().create(prop2);
System.out.println("prop set");
//props saved


Client client = new Client();
client.setName("cascadeable");
client.setComment("ho-ho-ho");
client.setActivated(false);
//cli set
Set<AdditionalProperty> propList = new HashSet<>();
prop.setClient(client);
prop2.setClient(client);
propList.add(prop);
propList.add(prop2);
// props added to list
client.setPropertiesList(propList);
// list added to client
HibernateDAOClient dao = new HibernateDAOClient();
dao.create(client);

查询结果不是我所期望的:

Hibernate: insert into user_properties (property_name, property_type) values (?, ?)
Hibernate: insert into user_properties (property_name, property_type) values (?, ?)
prop set
Hibernate: insert into client (client_activated, client_comment, client_name) values (?, ?, ?)

我期望的地方:

Hibernate: insert into ref_client_to_prop (id_client, id_prop) values (?, ?)

请帮忙,我做错了什么?我需要将他们的关系保存在数据库中,但不知何故我不能。

附注增加困惑:

当我使用这个类时:

public class ClientProperty {
@Id
@Column(name = "ID")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private int id;
@ManyToOne(cascade=CascadeType.ALL)
@JoinColumn(name="id_client")
private Client client;
@ManyToOne(cascade=CascadeType.ALL)
@JoinColumn(name="id_characteristic")
private AdditionalProperty property;
@Column(name = "characteristic_value")
private String value;

然后执行(添加到前面的代码中):

System.out.println("try to save");
ClientProperty cliPro = new ClientProperty();
cliPro.setClient(client);
cliPro.setProperty(prop);
cliPro.setValue("vocabulary");
DAOInterface<ClientProperty> daocp = new HibernateDAOClientProperty();
daocp.create(cliPro);

我神奇地得到了我想要的东西。不知道怎么办。

Hibernate: insert into client_characteristic_filled (id_client, id_characteristic, characteristic_value) values (?, ?, ?)
Hibernate: update client set client_activated=?, client_comment=?, client_name=? where client_id=?
Hibernate: update user_properties set property_name=?, property_type=? where property_id=?
Hibernate: update ref_client_to_prop set id_client=? where id_prop=?
Hibernate: insert into ref_client_to_prop (id_client, id_prop) values (?, ?)

最佳答案

在第一种情况下,您在事务内、刚刚从同一事务中保存的图书上设置图书的学生。因此,该书附于本次 session 。因此,Hibernate 会跟踪其状态的所有更改,当您提交时,它会注意到该书的客户端已设置,从而保存关联。

在第二种情况下,您没有任何交易。您创建一个属性,一旦 DAO 的事务完成,该属性就变成一个独立的对象,即 Hibernate 不知道的普通旧对象,其状态根本不被跟踪。然后,您在此分离的对象上设置属性的客户端。但 Hibernate 对此一无所知,因此它不会插入关联。

请注意,设置客户端属性并保存客户端不会保存关联,因为双向关联的拥有方是 Property.client,而不是 Client.properties。而 Hibernate 只关心拥有方。

尽可能避免使用分离的对象。在业务方法的开头启动一个事务,然后使用 Hibernate,仅附加对象,然后提交事务。

关于java - hibernate,无法保存多对一关系,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34239253/

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