java - 线程中的异常 "main"java.lang.StringIndexOutOfBoundsException : String index out of range:

Question

我的代码是:

import java.util.*;
public class Lab4Exercise {

public static String reverseString(String a){
    int x = a.length();
    String b = "";
    while(x > 0){
        int y = x - 1;
        b = b + a.charAt(y);
        x--;
    }
    return b;
}
public static String encrypt(String a){
    String a1 = a.replaceAll("\\p{Punct}+", "");
    String a2 = a1.replaceAll(" ", "");
    String str = "";
    String str2 = "";
    if(a.length() % 2 == 0){
        for(int q = 0; q <= a2.length(); q += 2){
            str = str + a.charAt(q);
    }
        for(int w = 1; w < a2.length(); w += 2){
            str2 = str2 + a.charAt(w);
    }
        return str.concat(str2);
}
    else{
        for(int z = 0; z < a2.length(); z += 2){
            str2 = str2 + a.charAt(z);
        }
        for(int c = 1; c <= a2.length(); c += 2){
            str2 = str2 + a.charAt(c);
        }
        return str.concat(str2);
    }
}
public static int countTool(String a){
    a = a.toLowerCase();
    int g = a.length();
    String str = "";        
    while(g >= 0){
        if(a.charAt(g) == 'a'){
            str = str + a.charAt(g);
        }
        g--;            
    }
    int h = str.length();
    return h;
}
public static double Equation(int n, int x){
    double a = 0, t = 0;
    if(n >= 0){
        double w = 0.0;
        for(int k = 0; k <= n; k++){
            a = Math.pow(x, k)*Math.pow(Math.E, (n - k));
            w = w + a;}
        return Math.abs(w);
    }
    else {
        double q = 0;
        for(int b = 0; b >= n; b--){
            t = Math.pow(x, b)*Math.pow(Math.E, (n - b));
            q = q + t;}
        return Math.abs(q);
    }
}

public static void main(String[] args) {
    Scanner scan = new Scanner(System.in);
    System.out.println("Enter case number: ");
    int caseVal = scan.nextInt();
    switch(caseVal){

    case 1:
        System.out.println("Enter a string to reverse: ");
        String str = scan.next();
        System.out.println("Reversed string is: " + reverseString(str));        
        break;

    case 2:
        System.out.println("Enter a string to encrypt");
        String str2 = scan.next();
        System.out.println("Encrypted text is: " + encrypt(str2));
        break;

    case 3:
        System.out.println("Enter a string to count: ");
        String str3 = scan.next();
        System.out.println(countTool(str3));
        break;

    case 4:
        System.out.println("Enter n value: ");
        int n = scan.nextInt();
        System.out.println("Enter x value: ");
        int x = scan.nextInt();
        System.out.println(Equation(n, x)); 
        break;

    case 5:
        Random random = new Random();
        int randomnum = 0;
        for(int p = 0; p < 50; p++){
            randomnum = 20 + (int)(Math.random()*119);
            System.out.println(Math.sqrt(randomnum));
        }
    }
}

}

因此，当我尝试执行案例 2 和案例 3 时，它会给出此错误:(例如，我在这两种情况下都选择了“我爱树!”)

Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 1
    at java.lang.String.charAt(Unknown Source)
    at Lab4Exercise.encrypt(Lab4Exercise.java:33)
    at Lab4Exercise.main(Lab4Exercise.java:84)

对于案例3:

Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 1
        at java.lang.String.charAt(Unknown Source)<br/>
        at Lab4Exercise.countTool(Lab4Exercise.java:43)<br/>
        at Lab4Exercise.main(Lab4Exercise.java:90)<br/>

Answer 1

第 33 行，您正尝试访问索引处不存在的数组。

改变

for(int c = 1; c <= a2.length(); c += 2){

到

 for(int c = 1; c <a2.length(); c += 2){

玩弄字符串的大小时要小心。如果字符串的大小为 8，这意味着您可以从索引 0 到 7 访问它，是的，在 Debug模式下运行代码并继续检查值，这确实会对您有所帮助。