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java - 从 Android 中的 StartActivityForResult 返回一个类

转载 作者:行者123 更新时间:2023-12-01 10:41:24 25 4
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我启动了一项 Activity ,从手机上的所有联系人列表中获取联系人。现在我的问题是如何从 ListView 中正确地将选定的检查直接返回到我的 Person 类中。我并不完全理解 Intent 和 Activity 的一般概念,所以请耐心等待。

这是我如何从 MainActivity.java 启动 Activity

static final int PICK_CONTACT_REQUEST = 1;
public void grabthecontacts(View view) {
Intent intent = new Intent(getApplicationContext(), SelectContactsActivity.class);
startActivityForResult(intent, 1);
}


@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {

if (requestCode == 1) {
if(resultCode == Activity.RESULT_OK){
String result=data.getStringExtra("result");
}
if (resultCode == Activity.RESULT_CANCELED) {
}
}
}

这是它调用的类,选择联系人 Activity

    package com.example.android.smsapp;

import android.content.Intent;
import android.database.Cursor;
import android.os.Bundle;
import android.app.Activity;
import android.provider.ContactsContract;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.Button;
import android.widget.CheckBox;
import android.widget.ListView;
import android.widget.TextView;

import java.util.ArrayList;
import java.util.HashSet;
import java.util.Set;

public class SelectContactsActivity extends Activity {

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_select_contacts);
populateListView();
Button SubmitButton = (Button) findViewById(R.id.submitbut);

SubmitButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
registerDoneClick(view);
}
});

}
ArrayList<Person> list = new ArrayList<>();
Set<Person> checkedlist = new HashSet<>();

public void populateListView() {
try {
Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, null, null, null);

while (phones.moveToNext()) {
String name = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
String phoneNumber = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
Person allcontacts = new Person(name, phoneNumber);
list.add(allcontacts);
}
phones.close();
}
catch (Exception e){
e.printStackTrace();
}


ListView listview2 = (ListView) findViewById(R.id.contactlistview);
ArrayAdapter<Person> adapter = new myListAdapter();
listview2.setAdapter(adapter);
listview2.setItemsCanFocus(false);
listview2.setChoiceMode(ListView.CHOICE_MODE_MULTIPLE);
}

public class myListAdapter extends ArrayAdapter<Person> {

public myListAdapter() {
super(SelectContactsActivity.this, R.layout.da_item, list);
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
View itemView = convertView;
if (itemView == null) {
itemView = getLayoutInflater().inflate(R.layout.da_item, parent, false);
}
// Find person wot work with
Person currentperson = list.get(position);

// Fill the view
TextView nameboxview = (TextView) itemView.findViewById(R.id.NameView);
nameboxview.setText(currentperson.getName());

TextView numberboxview = (TextView) itemView.findViewById(R.id.NumberView);
numberboxview.setText(currentperson.getPhone());
CheckBox cb = (CheckBox)itemView.findViewById(R.id.checkBox);
cb.setTag(position);

if (cb.isChecked()) {
currentperson.setChecked(true);
}


return itemView;
}
}

public void registerDoneClick(View view) {
for (Person allcontacts : list) {
if(allcontacts.isChecked()) {
Person human = new Person(allcontacts.getName(), allcontacts.getPhone());
}
}
// How do I return human with this activity? or is there another method?
finish();
}

}

我完全不知道如何返回我作为一个人想要的值(value)观,所以我只能这样做

hashsetname.add(human)

非常感谢任何帮助,即使是一般格式设置,或者任何 java 提示。谢谢

最佳答案

试试这个,

首先将 Person 类设为可序列化,使用

public class Person implements Serializable

现在像这样在 Intent 中设置 ivalue,

Intent returnIntent = new Intent();
returnIntent.putExtra("result", human);
setResult(Activity.RESULT_OK, returnIntent);
finish();

从 onActivityResult 方法中的 Intent 获取值,

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {

if (requestCode == 1) {
if(resultCode == Activity.RESULT_OK){

Person myObject = (Person) data.getParcelableExtra("result");
}
if (resultCode == Activity.RESULT_CANCELED) {
}
}
}

关于java - 从 Android 中的 StartActivityForResult 返回一个类,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34389134/

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