Java - Oracle SQL - SQL 命令未正确结束

Question

我的 Java 应用程序中有以下代码:

String query = "select name from BusinessRuleType where businessRuleTypeId = "+id+";";
        ResultSet rs = stmt.executeQuery(query);

现在，当我从 Oracle SQL Developer 中执行此操作时，(代码:select name from BusinessRuleType wherebusinessRuleTypeId = 5; 然后我将得到结果。

我的 Eclipse 给了我这个错误；

java.sql.SQLSyntaxErrorException: ORA-00933: SQL command not properly ended

at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:450)
at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:399)
at oracle.jdbc.driver.T4C8Oall.processError(T4C8Oall.java:1017)
at oracle.jdbc.driver.T4CTTIfun.receive(T4CTTIfun.java:655)
at oracle.jdbc.driver.T4CTTIfun.doRPC(T4CTTIfun.java:249)
at oracle.jdbc.driver.T4C8Oall.doOALL(T4C8Oall.java:566)
at oracle.jdbc.driver.T4CStatement.doOall8(T4CStatement.java:202)
at oracle.jdbc.driver.T4CStatement.doOall8(T4CStatement.java:45)
at oracle.jdbc.driver.T4CStatement.executeForDescribe(T4CStatement.java:766)
at oracle.jdbc.driver.OracleStatement.executeMaybeDescribe(OracleStatement.java:897)
at oracle.jdbc.driver.OracleStatement.doExecuteWithTimeout(OracleStatement.java:1034)
at oracle.jdbc.driver.OracleStatement.executeQuery(OracleStatement.java:1244)
at oracle.jdbc.driver.OracleStatementWrapper.executeQuery(OracleStatementWrapper.java:420)
at persistence.tool.ToolDAO.getOperator(ToolDAO.java:106)
at persistence.tool.ToolDAO.getAll(ToolDAO.java:40)
at persistence.tool.ToolService.getAll(ToolService.java:11)
at controller.Controller.getAllRules(Controller.java:29)
at servlets.ExecuteServlet.doGet(ExecuteServlet.java:18)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:624)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:731)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:303)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:208)
at org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:241)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:208)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:220)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:122)
at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:505)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:170)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:103)
at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:956)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:116)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:423)
at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1079)
at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:625)
at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:316)
at java.util.concurrent.ThreadPoolExecutor.runWorker(Unknown Source)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(Unknown Source)
at org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61)
at java.lang.Thread.run(Unknown Source)

我的 Java 代码有什么问题，或者使用准备好的语句是否更好，这是否可以解决问题？

Answer 1

只需尝试删除最后一个分号

String query = "select name from BusinessRuleType where businessRuleTypeId = "+id;