java - 如何从 XML 文件中删除 XML 标签而不对标签名称进行硬编码

Question

我需要使用Java删除XML文件中的所有OBJECT标签。当我直接输入父标签名称(SPAN)时，我可以删除OBJECT标签 直接将代码硬编码到源代码(“span”)中，但是我需要删除没有硬代码父标签的标签。如果我硬编码，我只能删除span标签内的对象标签。我需要删除 XML 中的所有，即使它可能位于另一个父标签内，而无需硬编码源代码中的父标签。我需要删除示例 XML 文件中 span 标记和 score 标记内可用的所有 Object 标记。对于示例 XML 文件，请查看下面的图像。

Java程序

public class XmlObject {

public static void main(String[] args) {
    String filePath = "/Users/myXml/Sample.xml";
    File xmlFile = new File(filePath);
    DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
    DocumentBuilder dBuilder;
    try {
        dBuilder = dbFactory.newDocumentBuilder();
        Document doc = dBuilder.parse(xmlFile);
        doc.getDocumentElement().normalize();
        deleteElement(doc);
        doc.getDocumentElement().normalize();
        TransformerFactory transformerFactory = TransformerFactory.newInstance();
        Transformer transformer = transformerFactory.newTransformer();
        DOMSource source = new DOMSource(doc);
        StreamResult result = new StreamResult(new File("/Users/myXml/Sample_ObjDelete.xml"));
        transformer.setOutputProperty(OutputKeys.INDENT, "yes");
        transformer.transform(source, result);
        System.out.println("XML file updated successfully");

    } catch (SAXException | ParserConfigurationException | IOException | TransformerException e1) {
        e1.printStackTrace();
    }
}

private static void deleteElement(Document doc) {
    NodeList RootElement = doc.getElementsByTagName("assessmentItem");

    int getRootElementLength = RootElement.getLength();

        System.out.println("getRootElementLength "+getRootElementLength);

        for(int k = 0; k < getRootElementLength; k++){
            System.out.println("2");
            Node nNode = RootElement.item(0);

            Element eElement = (Element) nNode;
            NodeList object = eElement.getElementsByTagName("span");
            Element obj = null;


    for(int i=0; i<object.getLength();i++){
        obj = (Element) object.item(i);
        int leng = obj.getElementsByTagName("object").getLength();
            System.out.println("object:" +leng);
            for(int j=0; j<leng;j++){
                Node objectNode = obj.getElementsByTagName("object").item(k);
                (obj).removeChild(objectNode);
            }
    }
    }

}

}

<qualityTest>
<responseDeclaration>
<correctResponse>
<value>QualityTest</value>
</correctResponse>
</responseDeclaration>
<itemBody>
<sampleTest>
<p>Who is president of uganda?</P>
<span>
<object>
Yoweri Museveni</object>
<span>
<object>
Raúl Castro
</Object>
</span>
</sampleTest>
</itemBody>
<score>
<object>
Yingluck Shinawatra
</Object>
</score>
</qualityTest> 

Answer 1

您应该递归地遍历 xml 树并删除任何对象元素的所有出现:

private static void deleteElement(Node someNode) {
    NodeList childs = someNode.getChildNodes();
    for (int i = 0; i < childs.getLength();) {
        Node child = childs.item(i);
        if (child.getNodeType() == Document.ELEMENT_NODE) {
            if (child.getNodeName().equalsIgnoreCase("object")) {
                child.getParentNode().removeChild(child);
                continue;
            } else {
                deleteElement(child);
            }
        }
        i++;
    }
}

这个小代码片段将删除树中任意深度的任何名为“object”的 xml 标签。