java - 第一个 do-while 循环无法正常运行

Question

我的代码似乎有问题。我的代码检测到非整数并不断要求用户输入正数#，但是当您插入负数#时，它只要求用户输入正数一次。怎么了？肯定与我的 do-while 循环有关。我只关注第一个N，然后我可以做第二个N。

import java.util.Scanner;

public class scratch {

public static void main(String[] args) {

    Scanner input = new Scanner(System.in);

    int firstN = 0;
    int secondN = 0;
    boolean isNumber = false;
    boolean isNumPos = false;

    System.out.print("Enter a positive integer: ");

    do {
        if (input.hasNextInt()) {
            firstN = input.nextInt();
            isNumber = true;
        }
        if (firstN > 0) {
            isNumPos = true;
            isNumber = true;
            break;
        } else { 
            isNumPos = false;
            isNumber = false;
            System.out.print("Please enter a positive integer: ");
            input.next();
            continue;

        }

    } while (!(isNumber) || !(isNumPos));

    System.out.print("Enter another positive integer: ");
    do {
        if (input.hasNextInt()) {
            secondN = input.nextInt();
            isNumber = true;
        }
        if (secondN > 0) {
            isNumPos = true;
            isNumber = true;
        } else {
            isNumPos = false;
            isNumber = false;
            System.out.print("Please enter a positive integer: ");
            input.next();
        }

    } while (!(isNumber) || !(isNumPos));

    System.out.println("The GCD of " + firstN + " and " + secondN + " is " + gCd(firstN, secondN));

}

public static int gCd(int firstN, int secondN) {
    if (secondN == 0) {
        return firstN;
    } else
        return gCd(secondN, firstN % secondN);
}

}

Answer 1

在这种情况下，您读取输入两次:

        firstN = input.nextInt();
        ...
        input.next ();

添加一些指示变量或重新组织代码，以便当您通过第一次读取时，避免第二次读取。