java - 从十六进制转换为二进制以及二进制到十六进制，不使用转换，读取txt文件以查找RAM中的错误

Question

我正在尝试创建一个 java 程序，该程序将计算机中 RAM 位置中可能存在的错误转换为十六进制。然后从十六进制切换到二进制，再从二进制切换到十进制，以找到损坏的 RAM 的位置。这是我到目前为止的代码:

public class Practice {

private static String result;
private static int j;

public static void hexToBinary() throws IOException {
Scanner infile = new Scanner(new File("RAMerrors.txt"));

result = "";
String binVal; // the binary value of the Hex

while (infile.hasNextLine()) {
    String line = infile.nextLine();
    Scanner input = new Scanner(line);
    String hex = input.next();

    for (int i = 0; i < hex.length(); i++) {
        char hexChar = hex.charAt(i);

        switch (hexChar) {
            case ('0'):
                binVal = "0000";
                break;
            case ('1'):
                binVal = "0001";
                break;
            case ('2'):
                binVal = "0010";
                break;
            case ('3'):
                binVal = "0011";
                break;
            case ('4'):
                binVal = "0100";
                break;
            case ('5'):
                binVal = "0101";
                break;
            case ('6'):
                binVal = "0110";
                break;
            case ('7'):
                binVal = "0111";
                break;
            case ('8'):
                binVal = "1000";
                break;
            case ('9'):
                binVal = "1001";
                break;
            case ('A'):
                binVal = "1010";
                break;
            case ('B'):
                binVal = "1011";
                break;
            case ('C'):
                binVal = "1100";
                break;
            case ('D'):
                binVal = "1101";
                break;
            case ('E'):
                binVal = "1110";
                break;
            case ('F'):
                binVal = "1111";
                break;
            default:
                binVal = "invalid input";
                break;


        }
         result += binVal;
    }
    System.out.println("Binary of " + hex + ":" + result);

  }

 }

public static void binaryToDecimal() {
    double j=0;
for(int i=0;i<result.length();i++)
{
    if(result.charAt(i)== '1')
    {
     j= j + Math.pow(2, result.length()-1-i);
    }

}
System.out.println("Decimal value: " + j);

}




public static void main(String arg[]) throws IOException {

    hexToBinary();
    binaryToDecimal();
}

}

十六进制到二进制没问题。小数部分只显示一个数字(而且它不是正确的值)。不太确定使用什么循环或如何将二进制运行到十进制部分。预先感谢您的任何建议! txt 文件具有以下值:

ABCDEFABC
1A00D0000
7A0EDF301
3CDAEFFAD

Answer 1

好吧，你的问题我不清楚。您只得到一个号码的原因是您从 main 调用电话。至hexToBinary ，使用此方法循环遍历整个文件，然后返回到 main 。之后，您调用binaryToDecimal它打印出 result 的值，这是它从 hexToBinary 获得的最后一个值.
您需要做的是从文件中读取一个值，将其转换为二进制，然后转换为十进制，然后继续处理下一个值。一种方法是这样的:
更改您的方法以返回值并获取参数。
hexToBinary应该是 -

public static String hexToBinary(String hex) throws IOException {
    String result = "";
    String binVal; // the binary value of the Hex
    for (int i = 0; i < hex.length(); i++) {
        char hexChar = hex.charAt(i);

        switch (hexChar) {
            case ('0'):
                binVal = "0000";
                break;
            case ('1'):
                binVal = "0001";
                break;
            case ('2'):
                binVal = "0010";
                break;
            case ('3'):
                binVal = "0011";
                break;
            case ('4'):
                binVal = "0100";
                break;
            case ('5'):
                binVal = "0101";
                break;
            case ('6'):
                binVal = "0110";
                break;
            case ('7'):
                binVal = "0111";
                break;
            case ('8'):
                binVal = "1000";
                break;
            case ('9'):
                binVal = "1001";
                break;
            case ('A'):
                binVal = "1010";
                break;
            case ('B'):
                binVal = "1011";
                break;
            case ('C'):
                binVal = "1100";
                break;
            case ('D'):
                binVal = "1101";
                break;
            case ('E'):
                binVal = "1110";
                break;
            case ('F'):
                binVal = "1111";
                break;
            default:
                binVal = "invalid input";
                break;
        }
         result += binVal;
    }
    return result;
  }

binaryToDecimal应该是-

public static Double binaryToDecimal(String result) {
    double j=0;
for(int i=0;i<result.length();i++)
{
    if(result.charAt(i)== '1')
    {
     j= j + Math.pow(2, result.length()-1-i);
    }

}
return j;
}

还有main将读取文件，将值传递给这两个方法并打印结果:

    public static void main(String args[]) throws IOException {

    Scanner infile = new Scanner(new File("RAMerrors.txt"));
    String result;
    Double decimal;

    while (infile.hasNextLine()) {
        String line = infile.nextLine();
        Scanner input = new Scanner(line);
        String hex = input.next();
        result = hexToBinary(hex);
        System.out.println("Binary of " + hex + ":" + result);
        decimal = binaryToDecimal(result);
        System.out.println("Decimal value: " + decimal);            
    }

输出为

Binary of ABCDEFABC:101010111100110111101111101010111100 Decimal value: 4.6118402748E10 Binary of 1A00D0000:000110100000000011010000000000000000 Decimal value: 6.980173824E9 Binary of 7A0EDF301:011110100000111011011111001100000001 Decimal value: 3.2764719873E10 Binary of 3CDAEFFAD:001111001101101011101111111110101101 Decimal value: 1.6335699885E10

希望这对您有帮助。