java - 如何除以两个 float 并得到一个整数

Question

我有两个都是 float 的变量，我希望除法以整数形式返回。我尝试了一些方法，例如 Math.Round() 并将其乘以 1，然后除以 1，我似乎无法让它工作。

  import java.util.Scanner;

  public class Calculator
  {
     public static void main (String[] args)
     {

        float firstNumber;
        float secondNumber;
        char operator;
        float answer;
        float answerRemainder;
        Scanner input = new Scanner (System.in);


        System.out.print("Enter your first number");
        firstNumber = input.nextInt();
        System.out.print("Enter the operator (s for subtraction, a for addition, m for multiplication, d for division, r for division with a remainder))\n");
        operator = input.next().charAt(0);
        while (operator != 's' && operator != 'a' && operator != 'm' && operator != 'd' && operator != 'r')

        {
           System.out.print("\nYou have entered an incorrect character. Enter the operator (s for subtraction, a for addition, m for multiplication, d for division, r for division with a remainder)\n");
           operator = input.next().charAt(0);
        }

        System.out.print("Enter your second number");
        secondNumber = input.nextInt();

        if (operator == 's')

        {
           System.out.print(firstNumber +" - "+secondNumber+" = "+(firstNumber - secondNumber));
        }

        else if (operator == 'a')

        {
           System.out.print(firstNumber +" + "+secondNumber+" = "+(firstNumber + secondNumber));
        }

        else if (operator == 'm')

        {
           System.out.print(firstNumber+" * "+secondNumber+" = "+(firstNumber * secondNumber));
        }      

        else if (operator == 'd')

        {
           System.out.print(firstNumber+" / "+secondNumber+" = "+(firstNumber / secondNumber));
        }

        else if (operator == 'r')

        {
            answerRemainder = (firstNumber / secondNumber);
            System.out.print(firstNumber+" / "+secondNumber+" = "+(answerRemainder)+" with a remainder of "+(firstNumber % secondNumber));
        }
     }
  }

所以我希望最后一行“answerRemainder”是一个整数

Answer 1

您可以将除法转换为 int，例如 answerRemainder = (int) (firstNumber/secondaryNumber);

尽管如此，正如问题评论中指出的那样，执行上述操作将导致精度损失。

在没有任何转换的情况下，如果 firstNumber = 3.4f 和 secondNumber = 1.2f，firstNumber/secondaryNumber 的结果将为 2.8333333.

使用强制转换，结果将是 2.0，因为 int 是没有精度的数字，因此结果会被截断并丢弃精度。

使用 ceiling 将结果向上舍入(Math.ceil)，结果将向上舍入，您将在之后得到整数2.8333333，其中将是 3.0。

使用 floor 将结果向下舍入(Math.floor)，结果将向下舍入，您将得到之前 2.8333333 的整数，其中将是 2.0。

注意:两个变量值上的 f 是必需的，因为如果没有它，默认情况下 Java 会将这些值解释为 double .