java - Java 中的 JSON Post 401 错误(未经授权)

Question

这个问题已经有答案了:

Http Basic Authentication in Java using HttpClient? (10 个回答)

已关闭 7 年前。

因此，我尝试发布到某个 URL(我无法显示该 URL，因为它是敏感信息)，但我不断收到 401 错误，这意味着未经授权。我有凭据，但我不知道如何设置它们。我有用户名、密码和角色。

public class GSONPost {

public static void main(String[] args) {

    Person personObj = new Person();
    personObj.setOrganization("ACC");
    personObj.setFirstName("Harry");
    personObj.setLastName("Smith");
    personObj.setPhone1(null);
    personObj.setPhone2(null);
    personObj.setEmail(null);
    personObj.setState("AZ");
    personObj.setLeadDate(null); // Fix Later
    personObj.setCompany("Dan's Mortage");
    personObj.setCompanyContactName("Indiana Jones");
    personObj.setOutsideRep("Joel Martin");

    Person personObj2 = new Person();
    personObj2.setOrganization("ACC");
    personObj2.setFirstName("Richard");
    personObj2.setLastName("Nixon");
    personObj2.setPhone1(null);
    personObj2.setPhone2(null);
    personObj2.setEmail(null);
    personObj2.setState(null);
    personObj2.setLeadDate(null); // Fix Later
    personObj2.setCompany("Dan's Mortage");
    personObj2.setCompanyContactName("Indiana Jones");
    personObj2.setOutsideRep("Joel Martin");

    List<Person> personArrayList = new ArrayList<Person>();
    personArrayList.add(personObj);
    personArrayList.add(personObj2);

    PersonList personList = new PersonList();
    personList.setPersonList(personArrayList);

    Gson gson = new GsonBuilder().setPrettyPrinting().create();

    String json = gson.toJson(personList);

    try {
        // write converted json data to a file named "PersonList.json"
        FileWriter writer = new FileWriter("C:\\Users\\Dylan\\JsonFiles\\PersonList.json");
        writer.write(json);
        writer.close();

    } catch (IOException e) {
        e.printStackTrace();
    }

    try

    {


        DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpPost postRequest = new HttpPost(
                "https://myurl/addlist");

        StringEntity input = new StringEntity(json);
        input.setContentType("application/json");
        postRequest.setEntity(input);

        HttpResponse response = httpClient.execute(postRequest);

        BufferedReader br = new BufferedReader(new InputStreamReader((response.getEntity().getContent())));

        String output;
        System.out.println("Output from Server .... \n");
        while ((output = br.readLine()) != null) {
            System.out.println(output);
        }

        httpClient.getConnectionManager().shutdown();

    } catch (MalformedURLException e) {

        e.printStackTrace();

    } catch (IOException e1) {

        e1.printStackTrace();

    }
}
}

如果有人可以告诉我一种设置凭据的方法，这样我就不会收到 401 错误，或者如果你们可以看到导致问题的其他任何内容并可以让我知道，那就太好了。提前致谢。

Answer 1

您需要在调用电话之前配置 SSL 设置。目前，您的 POST 很可能在 SSL 握手期间失败。一个快速解决方法是信任所有证书。这是一个代码片段，可以做到这一点:

SSLContextBuilder builder = new SSLContextBuilder();
builder.loadTrustMaterial(null, new TrustSelfSignedStrategy());
SSLConnectionSocketFactory sslsf = new SSLConnectionSocketFactory(builder.build());
CloseableHttpClient httpClient = HttpClients.custom().setSSLSocketFactory(sslsf).build();

HttpPost postRequest = new HttpPost("https://myurl/addlist");

StringEntity input = new StringEntity(json);
input.setContentType("application/json");
postRequest.setEntity(input);

HttpResponse response = httpClient.execute(postRequest);