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java - 同时获取所有通知

转载 作者:行者123 更新时间:2023-12-01 10:15:57 25 4
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我已使用事件警报管理器设置通知。如果我在不同时间设置多个通知,那么最后一个通知也会在最后一个通知中出现。

此外,如果开关关闭,我想取消特定通知。我也有同样的 Intent 取消通知。但我认为所有通知都被取消了。

我还创建了时间表,并使用时间表的 ID 创建事件。现在,如果我删除一个时间表,我想删除为属于已删除时间表的事件设置的所有通知。

设置闹钟:

public void setNotificationTime(Calendar c)
{

Date dateFrom = new Date();
df = new SimpleDateFormat("E MMM dd HH:mm:ss zzzz yyyy");
try {
dateFrom = df.parse(startTime);
}
catch (ParseException ex) {

}

dateFrom.getTime();
c.setTime(dateFrom);

hour = c.get(Calendar.HOUR_OF_DAY);
minute = c.get(Calendar.MINUTE);

if(notificationTime !=null && !notificationTime.isEmpty()) {


if (notificationTime.equals("10 Minutes Before")) {

FLAG = 1;

c.set(Calendar.HOUR_OF_DAY, hour);
c.set(Calendar.MINUTE, minute - 10);
c.set(Calendar.SECOND, 0);
c.set(Calendar.MILLISECOND, 0);
c.set(Calendar.DATE, day);
// c.set(Calendar.DAY_OF_WEEK,);

SetDay(c);

notification = c.getTime();
notificationTime = df.format(notification);

// setAlarm(c, FLAG);
Intent intent = new Intent(getBaseContext(), NotificationReceiver.class);
PendingIntent pendingIntent = PendingIntent.getBroadcast(getBaseContext(), RQS_1, intent, 0);
AlarmManager alarmManager = (AlarmManager) getSystemService(Context.ALARM_SERVICE);
alarmManager.setInexactRepeating(AlarmManager.RTC_WAKEUP, c.getTimeInMillis(), AlarmManager.INTERVAL_DAY * 7, pendingIntent);

Toast.makeText(getApplicationContext(), notificationTime, Toast.LENGTH_SHORT).show();


} else if (notificationTime.equals("30 Minutes Before")) {

FLAG = 2;

c.set(Calendar.HOUR_OF_DAY, hour);
c.set(Calendar.MINUTE, minute - 30);
c.set(Calendar.SECOND, 0);
c.set(Calendar.MILLISECOND, 0);
c.set(Calendar.DATE, day);
// c.set(Calendar.DAY_OF_WEEK,);

SetDay(c);

notification = c.getTime();
notificationTime = df.format(notification);

Intent intent = new Intent(getBaseContext(), NotificationReceiver.class);
PendingIntent pendingIntent = PendingIntent.getBroadcast(getBaseContext(), RQS_1, intent, 0);
AlarmManager alarmManager = (AlarmManager) getSystemService(Context.ALARM_SERVICE);
alarmManager.setInexactRepeating(AlarmManager.RTC_WAKEUP, c.getTimeInMillis(), AlarmManager.INTERVAL_DAY * 7, pendingIntent);

Toast.makeText(getApplicationContext(), notificationTime, Toast.LENGTH_SHORT).show();

// setAlarm(c,FLAG);

}

通知接收者

public class NotificationReceiver  extends BroadcastReceiver {


public static int MY_NOTIFICATION_ID = 0;
NotificationManager notificationManager;
Notification myNotification;

EventTableHelper db;

@Override
public void onReceive(Context context, Intent intent) {


Toast.makeText(context, "Time is set", Toast.LENGTH_LONG).show();

db = new EventTableHelper(context);

List<EventData> testSavings = db.getAllEvents();

for (EventData ts : testSavings) {
String log = "from date:" + ts.getFromDate()
+ " ,to date: " + ts.getToDate()
+ " ,location: " + ts.getLocation()
+ " ,title " + ts.getTitle();

Calendar c = Calendar.getInstance();
Date date = new Date();
Date date1 = new Date();
Log.d("Result: ", log);

SimpleDateFormat df = new SimpleDateFormat("E MMM dd hh:mm:ss zzzz yyyy");
SimpleDateFormat df2 = new SimpleDateFormat("hh:mm a");

try {
date = df.parse(ts.getFromDate());
date1 = df.parse(ts.getToDate());
} catch (ParseException ex) {

}
String timeFrom = df2.format(date);
// String startTime = String.valueOf(timeFrom);

String timeTo = df2.format(date1);
// String endTime = String.valueOf(timeTo);


String location = ts.getLocation();
String title = ts.getTitle();


Intent myIntent = new Intent(context, MainActivity.class);
PendingIntent pendingIntent = PendingIntent.getActivity(
context,
0,
myIntent,
PendingIntent.FLAG_UPDATE_CURRENT);

if(location.equals(""))
{
String msg = "From : " + timeFrom + "\nTo : " + timeTo;

myNotification = new NotificationCompat.Builder(context)
.setContentTitle("Event : " + title)
.setContentText(msg)
.setWhen(System.currentTimeMillis())
.setContentIntent(pendingIntent)
.setAutoCancel(true)
.setSmallIcon(R.drawable.eventicon)
.setSound(RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION))
.setStyle(new NotificationCompat.BigTextStyle().bigText(msg))
.setDefaults(Notification.DEFAULT_SOUND)
.build();

}

else
{
String msg = "From : " + timeFrom + "\nTo : " + timeTo + "\nAt : " + location;
myNotification = new NotificationCompat.Builder(context)
.setContentTitle("Event : " + title)
.setContentText(msg)
.setWhen(System.currentTimeMillis())
.setContentIntent(pendingIntent)
.setAutoCancel(true)
.setSmallIcon(R.drawable.eventicon)
.setSound(RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION))
.setStyle(new NotificationCompat.BigTextStyle().bigText(msg))
.setDefaults(Notification.DEFAULT_SOUND)
.build();

}

Log.i("Notify", "Notification");
notificationManager =
(NotificationManager) context.getSystemService(Context.NOTIFICATION_SERVICE);
notificationManager.notify(MY_NOTIFICATION_ID, myNotification);

myNotification.flags=Notification.FLAG_AUTO_CANCEL;

Intent i = new Intent();
i.putExtra("notificationId",MY_NOTIFICATION_ID);

MY_NOTIFICATION_ID ++;

}


}
}

最佳答案

每次调用broadcastReceiver时都会重置MY_NOTIFICATION_ID,因此所有通知都具有相同的ID,即0。我为避免这种情况所做的就是使用:

Random rand = new Random();
int id = rand.nextInt(1000000) + 1;

这样每个通知肯定会获得不同的 ID 号(它重复的几率是百万分之一)。

关于java - 同时获取所有通知,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35888388/

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