java - 重新启动程序/游戏

Question

我正在开发这个随机数猜测游戏。在游戏结束时，我希望用户可以选择再次玩(或让其他人玩)。我发现了几个类似的线程和问题，但没有一个能够帮助我解决这个小问题。我很确定我可以以某种方式使用我的 while 循环，但不知 Prop 体如何..

对 Java 非常陌生，所以请了解这是否是一个简单的修复方法..

   import java.util.Scanner;
   import java.util.Random;

public class GuessingGame {
public static void main(String[] args){

Random rand = new Random();
int correctNumber = rand.nextInt(100);
int numberOfGuesses = 0;
Scanner input = new Scanner(System.in);
int guess;
boolean win = false;    
String username = "";

    System.out.println("Hello, it is time to play a guessing game.");
    System.out.println("We will generate a random number between 0-99, and you will have to try to guess the number in as few attempts as possible.");
    System.out.println("You can also choose to give up by pressing \"q\" on your keyboard. \n\nTo get started, press \"s\" on your keyboard.");
    input.nextLine();

    System.out.println("\nEnter a username: ");
    username = input.nextLine();
    System.out.println("\nNew username registered: " + username);


    while(win == false){

    System.out.println("\nGuess a number between 0-99: ");
    guess = input.nextInt();
    numberOfGuesses++;

    if (guess == correctNumber){
        win = true;
    }
     else if(guess < correctNumber){
        System.out.println("Too low. Try again!");   
    }else if(guess > correctNumber){
        System.out.println("Too high. Try again!");   
    }
    }

    System.out.println("\nYou guessed the correct number which was " + correctNumber + ". Congrats!");
    System.out.println("\n" + username + " your number of guesses were: " + numberOfGuesses);

    win = false;
        }

 //     System.out.println("\nTo play again (let someone else try) press      \"s\", to quit press \"q\".");
 //     input.nextLine();
  //    if (input.next().equalsIgnoreCase("q")){
 //     System.out.println("\nThanks for playing!");
 //     }
 //     }else if(input.nextLine().equalsIgnoreCase("s")){       

    }

 //}    

Answer 1

您所描述的称为“游戏循环”。基本上，您会将整个游戏包装在一个循环中，该循环将根据某些条件重复。在这种情况下，条件是用户是否想再次玩。

在 Java-ish 伪代码中，结构如下所示:

boolean keepPlaying = true;
while (keepPlaying) {

    boolean hasWon = false;
    while (!hasWon) {
        // play a round in the game
    }

    keepPlaying = promptUser("Would you like to play again?");
}

该伪代码的“伪”部分当然是最后一行。只需询问用户是否想再玩一次，并将响应转换为游戏循环使用的逻辑值。

所以游戏本身就是一个“回合”循环，不断重复直到发生胜利或失败。 程序是一个“游戏”循环，不断重复直到用户退出。