java - 披萨订购计划

Question

public class PizzaEx {

/**
 * @param args the command line arguments
 */
public static void main(String[] args) {
   char letter;
   String input;
   int sizeD;
   int pizzaCount=1;
   Pizza pieOne;

   do{
       sizeD = getValidSize();
       input = JOptionPane.showInputDialog(null, "What type of topping do you wish to order? " +
                                                 "\n Green Pepper" +
                                                 "\n Mushroom"+
                                                 "\n Sausage"+
                                                 "\n Pepperoni"+
                                                 "\n Plain");

       pieOne = new Pizza(sizeD, input);
       System.out.println(pieOne);
       System.out.println("The Number of pizzas made are " + pieOne.getPizzaCount() +"."+"\n");
       input = JOptionPane.showInputDialog(null, "Do you wish to continue?\n "+
                                                 "'y' or 'Y' for YES\n"+
                                                 "'n' or 'N' for NO\n");
       letter = input.charAt(0);

           pizzaCount = pizzaCount +1;
   }
   while (letter == 'Y'|| letter == 'y');

   System.exit(0);
}

private static int getValidSize()
{
    int d;
    String input;
    do{
        input = JOptionPane.showInputDialog(null, "What size of pizza do you wish to order? "+
                                                  "\n 9 inch"+
                                                  "\n 12 inch"+
                                                  "\n 16 inch");
        d = Integer.parseInt(input);
    } while (!(d==9 || d==12 || d==16));
    return d;
}

所以上面是我的主要类(class)

public class Pizza {



    private int diameter;
    private int numOfPizza;
    private double price;
    private String tops;

Pizza(int sizeD, String input) {
    diameter = sizeD;
    tops = input;

}

public int getDiameter(){
    return diameter;
}

/**
 *
 * @param pizzaCount
 * @return
 */
public int getPizzaCount(){
    return numOfPizza;
}
public double getPrice(){
    return price;
}
public String getToppings(){
    return tops;
}
public void setDiameter(int sizeD){
    if (sizeD == 9)
        diameter = 9;
    else if ( sizeD == 12)
        diameter = 12;
    else if (sizeD == 15)
        diameter = 15;
    else
        diameter = 0;
    }    
public void setPizzaCount(int pizzaCount){
    numOfPizza = pizzaCount;
}
public void setPrice(double total){
    price = total;
}
public void setToppings(String input){
    if ("green pepper".equalsIgnoreCase(input))
        tops = "Green Pepper";
    else if ("mushroom".equalsIgnoreCase(input))
        tops = "Mushroom";
    else if ("sausage".equalsIgnoreCase(input))
        tops = "Sausage";
    else if ("pepperoni".equalsIgnoreCase(input))
        tops = "Pepperoni";
    else 
        tops = "Plain";
}
private double calculatePrice(int sizeD, String input){
    double total;
    if (sizeD == 9 && (tops).equalsIgnoreCase("plain")) 
        total = 5.95;
    else if (sizeD == 9)
        total = 6.95;
    else if (sizeD == 12  && (tops).equalsIgnoreCase("plain") )
        total = 7.95;
    else if (sizeD == 12)
        total = 8.95;
    else if (sizeD == 16 && (tops).equalsIgnoreCase("plain"))
        total = 9.95;
    else if (sizeD == 16)
        total = 10.95;
    else 
        total = 0.0;

    return total;
}
public String toString(){
    String pizzaString ="You have ordered a "+diameter + " inch pizza with "+tops +" toppings and a price of $"+ calculatePrice(diameter, tops);
    return pizzaString;
}

当我打印输出时，即使我设置了 pizzaCount = 1，它仍然显示制作的披萨数量 = 0。另外，当它要求浇头时，如果我输入除有效浇头选择之外的任何字符串 {"green椒", "mushroom", "sausage", "pepperoni", "plain"} 它将计算字符串作为配料，如果配料不是 {"green椒", "mushroom", "sausage", "pepperoni"} 以外的任何东西，则需支付配料费用 “普通”

这不是家庭作业或测试问题。这是我的教授布置的一些额外练习，并不是为了分数。我只是想要一些帮助来澄清为什么 String tops 没有被分配 setToppings() 方法调用的值。

Answer 1

使用getNumOfPizza()总是得到0的原因是因为你从不增加int numOfPizza，你只增加pizzaCount 在 main 中。

至于topping，即使您输入无效字符串，您仍要收取toppings费用的原因是您在calculatePrice中收取​​topping费用的逻辑if !equalsIgnoreCase("plain")。换句话说，除了“plain”之外的任何东西都将被视为配料。事实上，这个方法中的逻辑不必要地复杂，我建议你简化一些if语句:

private double calculatePrice(int sizeD, String input){
        if(!(tops).equalsIgnoreCase("plain")) {
            total = 1;
        } else {
            total = 0;
        }

        if(sizeD == 9) {
            total += 5.95;
        }

        else if(sizeD == 12) {
            total += 7.95;
        }

        else if(sizeD == 16) {
            total += 9.95;
        }

        return total;
    }