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java - 执行大整数 Java 程序时出现错误

转载 作者:行者123 更新时间:2023-12-01 10:09:37 24 4
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我编写了一个用于操作最多 40 位整数的 java 程序,但在编译时出现一些错误,我不知道为什么。你能帮我吗?下面我放了我的代码。包括两个类:

public class HugeInteger {

private int[] array = new int[40];

public HugeInteger() {
for (int i = 0; i <= 40; i++) {
array[i] = 0;
}

}

/**
*
* @param str
*/
public HugeInteger(String str) {

if (str.length() > 41) {
System.out.printf("More than 40 digits");
}

int i;
if (str.charAt(0) == '-') {
array[0] = -1;
} else if (str.charAt(0) != '0') {
array[0] = 1;
}
for (i = 0; i < 40; i++) {
if ((str.charAt(i) != '1') || (str.charAt(i) != '2') || (str.charAt(i) != '3') || (str.charAt(i) != '4') || (str.charAt(i) != '5') || (str.charAt(i) != '6') || (str.charAt(i) != '7') || (str.charAt(i) != '8') || (str.charAt(i) != '9') || (str.charAt(i) != '0')) {
System.out.printf("Not number");
break;
}

char chr = str.charAt(i);
Integer dig = Integer.parseInt(String.valueOf(chr));
array[i + 1] = dig;

}
}

/**
* This method overrides the toString and it is used for printing the
* object.
*
* @return string
*/
@Override
public String toString() {
String str = "";
for (int i = 0; i < 40; i++) {
str = str.concat(String.valueOf(array[i]));
}
return str;
}

/**
* This method adds two number together and returns their result.
*
* @param hg It's the second number to be added
* @return result After adding two number result will be saved in result.
*
*/
public HugeInteger Sum(HugeInteger hg) {
HugeInteger result = new HugeInteger();
int c = 0;
if (array[0] == 1 && hg.array[0] == 1) {
for (int i = 40; i >= 1; i--) {
result.array[i] = array[i] + hg.array[i] + c;
if (result.array[i] > 9) {
c = 1;
result.array[i] = result.array[i] % 10;
} else {
c = 0;
}

}
result.array[0] = 1;
} else if (array[0] == 1 && hg.array[0] == -1) {
hg.array[0] = 1;
result = Subtract(hg);
} else if (array[0] == -1 && hg.array[0] == 1) {
array[0] = 1;
result = Subtract(hg);
result.array[0] = (-1) * result.array[0];

} else if (array[0] == -1 && hg.array[0] == -1) {
for (int i = 40; i >= 1; i--) {
result.array[i] = array[i] + hg.array[i] + c;
if (result.array[i] > 9) {
c = 1;
result.array[i] = result.array[i] % 10;
} else {
c = 0;
}

}
result.array[0] = -1;

}

return result;
}

/**
* This method subtracts two number together and returns their result.
*
* @param hg It's the second number to be subtracted
* @return result After subtracting two number result will be saved in
* result.
*/
public HugeInteger Subtract(HugeInteger hg) {
HugeInteger result = new HugeInteger();
int c = 0;
if (array[0] == 1 && hg.array[0] == 1) {
if (array[1] > hg.array[1]) {
for (int i = 40; i >= 1; i--) {
if ((array[i] - c) < hg.array[i]) {
result.array[i] = (10 + array[i] - c) - hg.array[i];
c = 1;
} else {
result.array[i] = (array[i] - c) - hg.array[i];
c = 0;
}
}
for (int i = 0; i <= 40; i++) {
if (array[i] != 0) {
array[0] = 1;
break;
}

}

} else {
for (int i = 40; i >= 1; i--) {
if ((array[i] - c) < hg.array[i]) {
result.array[i] = (10 + hg.array[i] - c) - array[i];
c = 1;
} else {
result.array[i] = (hg.array[i] - c) - array[i];
c = 0;
}
}
result.array[0] = -1;
}
}

if (array[0] == 1 && hg.array[0] == -1) {
hg.array[0] = 1;
result = Sum(hg);
}

if (array[0] == -1 && hg.array[0] == 1) {
array[0] = 1;
result = Sum(hg);
result.array[0] = (-1) * result.array[0];
}

if (array[0] == -1 && hg.array[0] == -1) {
if (array[1] > hg.array[1]) {
for (int i = 40; i >= 1; i--) {
if ((array[i] - c) < hg.array[i]) {
result.array[i] = (10 + array[i] - c) - hg.array[i];
c = 1;
} else {
result.array[i] = (array[i] - c) - hg.array[i];
c = 0;
}
}
for (int i = 0; i <= 40; i++) {
if (array[i] != 0) {
array[0] = 1;
break;
}

}

} else {
for (int i = 40; i >= 1; i--) {
if ((array[i] - c) < hg.array[i]) {
result.array[i] = (10 + hg.array[i] - c) - array[i];
c = 1;
} else {
result.array[i] = (hg.array[i] - c) - array[i];
c = 0;
}
}
result.array[0] = -1;
}
result.array[0] = (-1) * result.array[0];
}
return result;
}

public int Sign(HugeInteger hg) {
return (hg.array[0]);
}

/**
* This method checks whether the first number is equal to the second one or
* not.
*
* @param hg It's the second number.
* @return a boolean that reveals that this condition is true or false.
*/
public boolean Equals(HugeInteger hg) {
boolean res = true;
for (int i = 0; i <= 40; i++) {
if (array[i] != hg.array[i]) {
res = false;
break;
}
}
return res;
}

/**
* This method checks whether the first number is greater than the second
* one or not.
*
* @param hg It's the second number.
* @return a boolean that reveals that this condition is true or false.
*/
public boolean isGreaterThan(HugeInteger hg) {

for (int i = 0; i <= 40; i++) {
if (array[i] > hg.array[i]) {
return true;
} else if (array[i] < hg.array[i]) {
return false;
} else {
i = i + 1;
}
}
return false;
}

/**
* This method checks whether the first number is less than the second one
* or not.
*
* @param hg It's the second number.
* @return a boolean that reveals that this condition is true or false.
*/
public boolean isLessThan(HugeInteger hg) {
for (int i = 0; i <= 40; i++) {
if (array[i] < hg.array[i]) {
return true;
} else if (array[i] > hg.array[i]) {
return false;
} else {
i = i + 1;
}
}
return false;
}

/**
* This method checks whether the number is zero or not.
*
* @param hg It's the number.
* @return a boolean that reveals that this condition is true or false.
*/
public boolean isZero(HugeInteger hg) {
if (array[0] == 0) {
return true;
}
return false;
}

}

主类:

public class Main {

private static ArrayList<String> String;

public static void main(String[] args) {

ArrayList<HugeInteger> num1 = new ArrayList<>();
ArrayList<HugeInteger> num2 = new ArrayList<>();
String line1, line2;
Scanner stdin = new Scanner(System.in);
line1 = stdin.nextLine();
line2 = stdin.nextLine();
System.out.printf("\n");
System.out.printf("\n");
HugeInteger a, b;
a = new HugeInteger(line1);
b = new HugeInteger(line2);
num1.add(a);
num2.add(b);
while (true) {
line1 = stdin.nextLine();
if (line1.equals("exit")) {
break;

}
line2 = stdin.nextLine();
System.out.printf("\n");
a = new HugeInteger(line1);
b = new HugeInteger(line2);
num1.add(a);
num2.add(b);

}
int index = 0;
HugeInteger c, d;

while (index < num1.size()) {
c = num1.get(index);
d = num2.get(index);
System.out.printf("Sum: ", c.Sum(d));
System.out.printf("Sub: ", c.Subtract(d));
System.out.printf("Equals : ", c.Equals(d));
System.out.printf("isGreaterThan: ", c.isGreaterThan(d));
System.out.printf("isLessThan: ", c.isLessThan(d));
index = index + 1;
}

}

}

最佳答案

只要看看你的问题,你就会在 HugeInteger 类中获取一个最多 40 位数字的字符串。我可以看到您正在尝试创建一个可以处理这么大的数字的新类,但是您的 HugeInteger 类仍然依赖于 Integer 因为您使用

Integer dig = Integer.parseInt(String.valueOf(chr));

Java 中的 Integer 类的最大值为 2147483647 和 -2147483647,因此使用 Integer 类解析 40 位字符串将完全失败。

您发布了很多代码,但本质上您尝试做的事情不会因为我刚才提到的原因而起作用,这将导致依赖于 HugeInteger 的所有其他类和方法无法提供正确或有效的答案。您需要重新考虑您的方法

关于java - 执行大整数 Java 程序时出现错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36215873/

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