java - 编写这些java数组的最佳方法是什么？

Question

我的类作业被困住了:

Create an application containing an array that stores eight integers. The application should

1. display all the integers, (done)
2. display all the integers in reverse order,
3. display the sum of the eight integers, (done)
4. display all values less than 5,
5. display the lowest value, (done)
6. display the highest value, (done)
7. calculate and display the average, (Done)
8. display all values that are higher than the calculated average value.

我必须使用(或尝试使用)数组；还必须至少使用一个循环来“遍历”(移动)数组。这也将于今晚山区标准时间 23:59 截止

我做错了什么？

package numberlistdemo;

import java.util.Arrays;

public class NumberListDemo 
{

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) 
    {
             int n[]= {1,2,3,4,5,6,7,8};
    int lowest = 1000;
    int highest = 0;
    int sum = 0;
    int five = 0;
    int OverF = 0;
    int rev = 0;
    int OverAve= 0;
    
        for (int i=0;i<n.length;i++)
           
        {
            
            int cur = n[i];
            if (cur < lowest) lowest = cur;
            if (cur > highest) highest = cur;
             sum += cur;
            
        }
         double ave = sum / n.length;
         
         for (int i=0;i<n.length;i++)
         {
            int cur = n[i];
            if (cur > ave) OverAve = cur;
         }
         
       for (int i=0;i<n.length;i++)
       {
          
           int LowF = n[i];
           if (LowF < 5) five = LowF;
           if (LowF > 5) OverF  = LowF;
       }
       
        
        
            //3
            System.out.println("Total of the Array is " + sum );
            //1
            System.out.println("The number we are using are " + Arrays.toString(n));
            //4
            System.out.println("All values lower the 5 are " + five );
            ////2
             for (int counter=n.length - 1; counter >= 0; counter--)
        {
           System.out.println("The reverse order of the numbers are " + (n[counter]));
        }         
             //5
            System.out.println("The lowest value is " + lowest);
            //6
            System.out.println("The highest value is "+ highest);
            //7
            System.out.println("The average is " + ave);     
            //8
            System.out.println("All numbers higher than the average are: " + OverAve);
           
  
    }
}

我明白了

Total of the Array is 36
The number we are using are [1, 2, 3, 4, 5, 6, 7, 8]
All values lower the 5 are 4
The reverse order of the numbers are 8
The reverse order of the numbers are 7
The reverse order of the numbers are 6
The reverse order of the numbers are 5
The reverse order of the numbers are 4
The reverse order of the numbers are 3
The reverse order of the numbers are 2
The reverse order of the numbers are 1
The lowest value is 1
The highest value is 8
The average is 4.0
All numbers higher than the average are: 8

Answer 1

从数组中获取总和、最低和最高整数的示例循环

int lowest = 1000;
int highest = 0;
int sum = 0;
for (int i = 0; i < array.length; ++i) {
  int cur = array[i];
  if (cur < lowest) lowest = cur;
  if (cur > highest) highest = cur;
  sum += cur;
}

编辑:最新的代码更新取得了一些进展，但可能不太满足指定的要求。了解完整的要求(例如输出格式)存在一些困难。

1. 仅输出

当前示例正在显示输出(每行一个条目)。目前尚不清楚是否只需要显示输出或实际反转数组。如果唯一的要求是输出反转，大于5和大于8的数字，则以下三个循环将起作用。其中大部分已经在建议的代码中。

System.out.println("The reversed array is: ");
for (int counter < n.length - 1; counter >= 0; counter--) {
    System.out.print(n[counter] + " ");
}
System.out.println();

请注意，这两个可能应该在一个方法中

final int lessThan = 5;
System.out.println("The numbers in the array less than " + lessThan + " are: ");
for (int i = 0; i < n.length; ++i) {
  if (n[i] < lessThan) {
    System.out.print(n[i] + " ");
  }
}
System.out.println();

System.out.println("The numbers in the array greater than the mean " + ave + " are: ");
for (int i = 0; i < n.length; ++i) {
  if (n[i] > ave) {
    System.out.print(n[i] + " ");
  }
}
System.out.println();

创建一个新的反转数组

对于需要实际反转数组的赋值来说更有意义。在这种情况下，有几种方法。也许最简单的方法是创建一个新数组并将元素反转到其中。本质上，它与上面的循环相同，但将 n 的元素放入数组中，而不是将它们输出到屏幕上。 (注:@Debosmit 提出了一个不需要额外索引变量的示例)。

int[] reversed = new int[n.length];
int idx = 0;
for (i = n.length - 1; i >= 0; --i) {
   reversed[idx++] = n[i]];
}

随后可以使用与显示所有原始条目相同的输出方法:

System.out.println("The reversed array is: " + Arrays.toString(reversed));