java - 将两个逗号分隔的字符串转换为 Map

Question

这个问题已经有答案了:

What is the best way to combine two lists into a map (Java)? (18 个回答)

已关闭 7 年前。

我有两个逗号分隔的字符串。我希望通过按索引绑定(bind)值将这些值放入映射中。一种方法是使用以下示例:

package com.test;

import java.util.ArrayList;
import java.util.Arrays;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

public class StringToMap {

    public static void main(String[] args) {
        String s1 = "1, 2, 3";
        String s2 = "a, b, c";
        Map<String, String> m = new HashMap<String, String>();

        List<String> s1List = new ArrayList<String>(Arrays.asList(s1.split(",")));
        List<String> s2List = new ArrayList<String>(Arrays.asList(s2.split(",")));

        for (int i = 0; i < s1List.size(); i++) {
            m.put(s1List.get(i).trim(), s2List.get(i).trim());
        }

        System.out.println(m);
    }
}

结果是:{3=c, 2=b, 1=a}。还有其他有效/最佳的方法吗？

Answer 1

你对此有何看法？

public static void main(String[] args) {
    String s1 = "1, 2, 3";
    String s2 = "a, b, c";
    Map<String, String> m = new HashMap<String, String>();
    String s1List [] = s1.split(",");
    String s2List [] = s2.split(",");
    for (int i = 0; i < s1List.length && i < s2List.length; i++) {
        m.put(s1List[i].trim(), s2List[i].trim());
    }
    System.out.println(m);
}