unix - 如何先移动文件的最后一行？

Question

我有一个按以下顺序包含 3 行的文件:

bsub -I -q vtran "vtran -scan_pad 0X ../test/pm30_60_224_jtag_bist_full_vector_off.vtran"
bsub -I -q vtran "vtran -scan_pad 0X ../test/pm30_60_224_jtag_bist_full_vector_on.vtran"
bsub -I -q vtran "vtran -scan_pad 0X ../test/pm30_60_224_jtag_bist_sanity_dft.vtran"

我必须按照以下顺序一一执行unix命令行中的所有行:

bsub -I -q vtran "vtran -scan_pad 0X ../test/pm30_60_224_jtag_bist_sanity_dft.vtran"
bsub -I -q vtran "vtran -scan_pad 0X ../test/pm30_60_224_jtag_bist_full_vector_off.vtran"
bsub -I -q vtran "vtran -scan_pad 0X ../test/pm30_60_224_jtag_bist_full_vector_on.vtran"

如何使用单个命令行重新排列和执行所有 3 个命令？

我已经按照你的建议尝试过:

line1: echo start 
line2: bsub -I -q vtran "vtran -scan_pad 0X ../test/pm30_60_224_jtag_bist_sanity_dft.vtran"
line3: echo hello 
line4: bsub -I -q vtran "vtran -scan_pad 0X ../test/pm30_60_224_jtag_bist_full_vector_off.vtran" 
line5: echo bye 
line6: bsub -I -q vtran "vtran -scan_pad 0X ../test/pm30_60_224_jtag_bist_full_vector_on.vtran" 
line7: echo end 

它仍然只执行第 1 行和第 2 行。之后退出那里..

Answer 1

您可以使用 tac (反向连接并打印文件)，在末尾打印第一项，然后反向返回:

tac file | awk 'NR==1 {line=$0; next} 1; END{print line}' | tac

更新

Thank you so much fedorqui answering for my first part of question. I can redirect the output of your command to a file & source it from the command line to execute one by one. instead Can you step forward and suggest a way to do it in a single command (without redirecting to a file & source)

您可以通过管道连接到 bash:

tac file | awk 'NR==1 {line =$0; next} 1; END{print line}' | tac | bash

例子

$ cat file
1
2
3

$ tac file | awk 'NR==1 {line =$0; next} 1; END{print line}' | tac
3
1
2

按件数:

逆转

$ tac file
3
2
1

最后打印第一项:

$ tac file | awk 'NR==1 {line=$0; next} 1; END{print line}'
2
1
3

逆转:

$ tac file | awk 'NR==1 {line =$0; next} 1; END{print line}' | tac
3
1
2