java - 我怎样才能把我的二进制，八进制和十六进制放在一个循环中

Question

所以我本周的目标是找到十进制的十六进制八进制和二进制。我能够获得十六进制、二进制和八进制，但它们是不同公共(public)类上的单独循环。所以我想知道如何使这段代码合一并在一个循环中读取十六进制、八进制和二进制。

<小时/>

十进制转十六进制

 import java.util.Scanner;
public class uncode {
public static void main (String[] args) {
    Scanner input = new Scanner(System.in);

    System.out.println("Enter a decimal number: ");
    int decimal = input.nextInt();

    String hex = "";

    while (decimal != 0 ) {
        int hexValue = decimal % 16;

        char hexDigit = (hexValue <= 9 && hexValue > 0) ?
                (char) (hexValue + '0') : (char)(hexValue - 10 + 'A');

                hex = hexDigit + hex;

                decimal = decimal / 16;
        }
    System.out.println("The hex number is " + hex);
    }
}

<小时/>

十进制转八进制

import java.util.Scanner;
public class octal {

    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        System.out.println("Enter a decimal number: ");
        int decimal = input.nextInt();
        String octal = "";

        while ( decimal > 0 ) {
            int remainder = decimal % 8;
            octal = remainder + octal;

            decimal = decimal / 8;
        }
        System.out.println("Octal number:  " + octal);
    }

}

<小时/>

十进制转二进制

 import java.util.Scanner;
    public class GuessNumbers {

        public static void main(String[] args) {
            Scanner input = new Scanner(System.in);
            System.out.println("Enter a decimal number: ");
            int decimal = input.nextInt();
            String binary = "";
            while (decimal > 0) {
                int remainder = decimal % 2;
                binary = remainder + binary;
                decimal = decimal / 2;
            }
            System.out.println("Binary number: " + binary);
        }

    }

Answer 1

例如，简单的方法是使用已经存在的转换

Scanner input = new Scanner(System.in);
System.out.println("Enter a decimal number: ");
int decimal = input.nextInt();
String hex = Integer.toHexString(decimal);
String oct = Integer.toOctalString(decimal);
String bin = Integer.toBinaryString(decimal);

如果您需要整数值，而不是字符串，则可以使用

int h = Integer.parseInt(hex, 16);
int o = Integer.parseInt(oct, 8);
int b = Integer.parseInt(bin, 2);

假设您不想使用这些方法(假设您有自己的理由)。

首先，您需要将代码放在方法中，而不是放在 main 中。

然后你可以这样做:

public class Class {
    public static void uncode() {
        Scanner input = new Scanner(System.in);

        System.out.println("Enter a decimal number: ");
        int decimal = input.nextInt();

        String hex = "";

        while (decimal != 0) {
            int hexValue = decimal % 16;

            char hexDigit = (hexValue <= 9 && hexValue > 0) ? (char) (hexValue + '0')
                    : (char) (hexValue - 10 + 'A');

            hex = hexDigit + hex;

            decimal = decimal / 16;
        }
        System.out.println("The hex number is " + hex);
    }

    public static void octal() {
        Scanner input = new Scanner(System.in);
        System.out.println("Enter a decimal number: ");
        int decimal = input.nextInt();
        String octal = "";

        while (decimal > 0) {
            int remainder = decimal % 8;
            octal = remainder + octal;

            decimal = decimal / 8;
        }
        System.out.println("Octal number:  " + octal);
    }

    public static void GuessNumbers() {
        Scanner input = new Scanner(System.in);
        System.out.println("Enter a decimal number: ");
        int decimal = input.nextInt();
        String binary = "";
        while (decimal > 0) {
            int remainder = decimal % 2;
            binary = remainder + binary;
            decimal = decimal / 2;
        }
        System.out.println("Binary number: " + binary);
    }

    public static void allInOne() {
        Scanner input = new Scanner(System.in);
        System.out.println("Enter a decimal number: ");
        int decimal = input.nextInt();
        int hex = decimal;
        int oct = decimal;
        int bin = decimal;

        String hexal = "";
        String octal = "";
        String binary = "";

        while (hex > 0 || oct > 0 || bin > 0) {
            if (hex > 0) {
                // Get Hexal
                int hexValue = hex % 16;

                char hexDigit = (hexValue <= 9 && hexValue > 0) ? (char) (hexValue + '0')
                        : (char) (hexValue - 10 + 'A');

                hexal = hexDigit + hexal;

                hex = hex / 16;
            }
            if (oct > 0) {
                // Get Octal
                int remainder = oct % 8;
                octal = remainder + octal;

                oct = oct / 8;
            }
            if (bin > 0) {
                // Get Binary
                int remainder = bin % 2;
                binary = remainder + binary;
                bin = bin / 2;
            }
        }
        System.out.println("The hex number is " + hexal);
        System.out.println("Octal number:  " + octal);
        System.out.println("Binary number: " + binary);
    }

    public static void main(String[] args) {
        uncode();
        octal();
        GuessNumbers();
        allInOne();
    }
}

我尝试对您的代码进行尽可能少的更改。