json - 在 Scala 中读取 JsValue

Question

我如何访问第一位居民的姓名？这是 Json 文件。以下是什么？

val bigwig = (json \ "residents")(1)..... 


import play.api.libs.json._

val json: JsValue = Json.parse("""
{
  "name" : "Watership Down",
  "location" : {
    "lat" : 51.235685,
    "long" : -1.309197
  },
  "residents" : [ {
    "name" : "Fiver",
    "age" : 4,
    "role" : null
  }, {
    "name" : "Bigwig",
    "age" : 6,
    "role" : "Owsla"
  } ]
}
""")

Answer 1

快速而肮脏(没有验证):

((jsonObject \ "residents").as[Seq[JsObject]].head \ "name").as[String]