java - 在java中加密字符串附加新行

Question

在主要部分:

String password = "spK47@wF";
    MessageDigest md;
    try {
        md = MessageDigest.getInstance("MD5");
        md.update(password.getBytes("UTF8"));
        byte[] digestedPwdBytes = md.digest();
        Base64 encoder = new Base64();
        System.out.print(new String(encoder.encode(digestedPwdBytes)) +":");
    } catch (NoSuchAlgorithmException e) {
        e.printStackTrace();
    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } 

所需输出:ymm/nnotV+vzSKnXtjubqA==:

我得到的输出:

ymm/nnotV+vzSKnXtjubqA==
:

如何删除多余的新行。为什么这一新行会附加到加密字符串中？

Answer 1

使用 Apache Commons Net

将行长度设置为0:

Base64 encoder = new Base64(0);
System.out.print(new String(encoder.encode(digestedPwdBytes)) +":");

输出:

ymm/nnotV+vzSKnXtjubqA==:

来自documentation

Line length: Default 76. Line length that aren't multiples of 4 will still essentially end up being multiples of 4 in the encoded data.

和

If lineLength <= 0, then the output will not be divided into lines (chunks). Ignored when decoding.

Apache Commons编解码器

或者使用Apache Commons Codec:org.apache.commons.codec.binary.Base64

Base64 encoder = new org.apache.commons.codec.binary.Base64();
System.out.print(new String(encoder.encode(digestedPwdBytes)) +":");