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python - 将语法与 SpeechRecognition 包一起使用时出现运行时错误

转载 作者:行者123 更新时间:2023-12-01 09:33:40 43 4
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因此,我尝试将语法与 speech_recognition.recognize_sphinx() 一起使用,但是,我收到以下错误:

RuntimeError: Decoder_set_fsg returned -1

这是我的代码:

Main.py

# Dependencies:
import speech_recognition as sr

# Collect audio sample
r = sr.Recognizer()
print('Please say "perquisition":')
with sr.Microphone() as source:
audio_en = r.listen(source)
print('Processing...')

# Attempt to convert the speech to text
try:
print(r.recognize_sphinx(audio_en, grammar='perquisition.gram'))
except sr.UnknownValueError:
print("Sphinx could not understand audio")
except sr.RequestError as e:
print("Sphinx error; {0}".format(e))

perquisition.gram

#JSGF V1.0;
grammar perquisition;
// Grammar rule names should be [a-zA-Z0-9] only!
public <perquisition> = ( perquisition );

对正在发生的事情有什么想法吗?

最佳答案

这里发生的一些事情掩盖了潜在的错误。speech_recognition.recognize_sphinx() 只是一些 CMUsphinx 命令的包装,可以在 here 找到。在第 746 行。这个确切的问题有点困惑,所以我们将重点关注下面的代码片段:

# Dependencies
import speech_recognition as sr
import os
import pocketsphinx as ps

# Manually point to the grammar file
grammar = 'search.gram'
try:
# Point to the model files
language_directory = os.path.join(os.path.dirname(os.path.realpath(__file__)), "pocketsphinx-data", "en-US")
acoustic_parameters_directory = os.path.join(language_directory, "acoustic-model")
language_model_file = os.path.join(language_directory, "language-model.lm.bin")
phoneme_dictionary_file = os.path.join(language_directory, "pronounciation-dictionary.dict")

# Create a decoder object with our custom parameters
config = ps.Decoder.default_config()
config.set_string("-hmm",
acoustic_parameters_directory) # set the path of the hidden Markov model (HMM) parameter files
config.set_string("-lm", language_model_file)
config.set_string("-dict", phoneme_dictionary_file)
config.set_string("-logfn", os.devnull) # <--- Prevents you from seeing the actual bug!!!
decoder = ps.Decoder(config)

# Convert grammar
grammar_path = os.path.abspath(os.path.dirname(grammar))
grammar_name = os.path.splitext(os.path.basename(grammar))[0]
fsg_path = "{0}/{1}.fsg".format(grammar_path, grammar_name)
if not os.path.exists(fsg_path): # create FSG grammar if not available
jsgf = ps.Jsgf(grammar)
rule = jsgf.get_rule("{0}.{0}".format(grammar_name))
fsg = jsgf.build_fsg(rule, decoder.get_logmath(), 7.5)
fsg.writefile(fsg_path)
print('Successful JSFG to FSG conversion!!!')

# Pass the fsg file into the decoder
decoder.set_fsg(grammar_name, fsg) # <--- BUG IS HERE!!!

except Exception as e:
print('Ach no! {0}'.format(e))
finally:
os.remove('search.fsg') # Remove again to help prove that the grammar to fsg conversion isn't at fault

运行该代码,我们发现 bug 弹出的行,而且日志信息已关闭!打开它后,大量文本会被转储到终端中,这可能会很麻烦。在这种情况下,重新打开它们以发现......

...
ERROR: "fsg_search.c", line 141: The word 'perquisition' is missing in the dictionary
...

现在我们已经取得进展了。这给我们留下了两个选择之一。首先,我们可以扫描字典(pocketsphinx.get_model_path()+'/cmudict-en-us.dict' 或类似的)来确定单词是否存在。然后我们可以决定是简单地忽略该单词,还是将其添加到字典中。

添加到字典中并不一定是直接的...根据它与字典中其他单词的相似程度,您可能能够摆脱它。否则,您还必须重新训练模型。关于如何执行此操作的更好解释可以在 here 中找到。 。享受吧。

关于python - 将语法与 SpeechRecognition 包一起使用时出现运行时错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49732605/

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