python - 如何在 Python 3 中计算并打印之间的颜色

Question

我是一名 Python 初学者。

我需要找到两个像素之间的 channel (红色、绿色、蓝色)差异，然后除以总像素数创建新像素。

我不知道应该使用什么条件或循环来打印输入像素之间的所有像素。

这是我到目前为止所写的内容:

p1 = int(input("Enter the first colour: "),16)
p2 = int(input("Enter the second colour: "),16)
colours = int(input("Enter the number of colours to generate inbetween: "))

red = (p1 & 0xFF0000) >> 16
green = (p1 & 0x00FF00) >> 8
blue = p1 & 0x0000FF
red2 = (p2 & 0xFF0000) >> 16
green2 = (p2 & 0x00FF00) >> 8
blue2 = p2 & 0x0000FF

red3 = abs(round(red-red2))/int(colours+1)
green3 = abs(round(green-green2))/int(colours+1)
blue3 = abs(round(blue-blue2))/int(colours+1)

print('0x%02x%02x%02x' % (red, green, blue))

这是一个输出示例:

Enter the first pixel: 0xFFDD33
Enter the second pixel: 0x002222
Enter the number of colours to generate inbetween: 3
Colours:
0x002222
0x405126
0x80802a
0xc0af2e
0xffdd33

Answer 1

尝试以下代码。它产生与样本类似的输出。差异主要是由于 float 的四舍五入造成的。

基本上，您需要确定两种颜色之间的差异。然后循环遍历 i=1 到 i=colors。通过每次添加差异来更新起始颜色。

p1 = int(input("Enter the first colour: "),16)
p2 = int(input("Enter the second colour: "),16)
colours = int(input("Enter the number of colours to generate inbetween: "))

red = (p1 & 0xFF0000) >> 16
green = (p1 & 0x00FF00) >> 8
blue = p1 & 0x0000FF
red2 = (p2 & 0xFF0000) >> 16
green2 = (p2 & 0x00FF00) >> 8
blue2 = p2 & 0x0000FF

red3 = abs((red2-red)/(colours+1))
green3 = abs((green2-green)/(colours+1))
blue3 = abs((blue2-blue)/(colours+1))

print('0x%02x%02x%02x' % (red, green, blue))
for i in range(1,colours+1):
    red += red3
    green += green3
    blue += blue3
    print('0x%02x%02x%02x' % (round(red), round(green), round(blue)))

print('0x%02x%02x%02x' % (red2, green2, blue2))