python :Sort filenames in a directory and add a number in the beginning of each filename

Question

1-intro-to deepleanring and computer visionk.MKV
2.Kaggle Deep Learning  - YouTube.MP4
Convolutional Neural Networks - Fun and Easy Machine Learning - YouTube.MP4
Convolutional Neural Networks - The Math of Intelligence (Week 4)YouTube.MKV
Introduction to Deep Learning- What Are Convolutional Neural Networks- YouTube.MP4
Kaggle Deep Learning 3 - YouTube.MP4
Kaggle Deep Learning 4 - YouTube.MP4
Kaggle Deep Learning 5 Data Augmentation - YouTube.MP4
Kaggle Deep Learning 6 - YouTube.MP4
Kaggle Deep Learning 7.mp4
Kaggle Deep Learning 8 - YouTube.MP4

这些是需要排序的文件。包含数字的文件名(在本例中为 3)Kaggle Deep Learning 3 -YouTube.MP4 应重命名为3 Kaggle深度学习 - YouTube.MP4。不包含任何数字的文件名或开头包含数字的文件不需要重命名。

到目前为止我已经编写了以下代码，但我被卡住了

for f in os.listdir():
    filename,extension = os.path.splitext(f))

简而言之，我希望这些文件在我的目录中看起来像这样..

1-intro-to deepleanring and computer visionk.MKV
2 Kaggle Deep Learning  - YouTube.MP4
3 Kaggle Deep Learning  - YouTube.MP4
4 Kaggle Deep Learning  - YouTube.MP4
5 Kaggle Deep Learning  Data Augmentation - YouTube.MP4
6 Kaggle Deep Learning  - YouTube.MP4
7 Kaggle Deep Learning .mp4
8 Kaggle Deep Learning  - YouTube.MP4
Convolutional Neural Networks - Fun and Easy Machine Learning - YouTube.MP4
Convolutional Neural Networks - The Math of Intelligence (Week 4)YouTube.MKV
Introduction to Deep Learning- What Are Convolutional Neural Networks- 
YouTube.MP4

Answer 1

这不是一个干净的示例，但它可能会帮助您，在您想要重命名文件的文件夹中运行它。

警告:运行代码之前请备份您的内容...

import os

dirs = os.listdir(".")

#I am splitting every string into a chr because we dont know the location of the number
split_dir= [list(f) for f in dirs]


print "split_dir", split_dir

y = split_dir

for index, x in enumerate(split_dir):
    for char in x:
        print "char", char
        if(char.isdigit()):
            print "inside is digit"

            y[index].remove(char)
            y[index].insert(0,char)


y = [''.join(x) for x in y]
print "split_dir", y


#this section just renames the files in the current working directory
for index,file_name in enumerate(dirs):
    print("yindex", y[index])
    os.rename(file_name, y[index])