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java - 比较字符串与数组字符串以及二分查找

转载 作者:行者123 更新时间:2023-12-01 09:29:31 25 4
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程序从排序字符串的 txt 文件中读取,并使用顺序、迭代二进制和递归二进制存储在数组中,然后在数组中搜索位置以及查找单词所需的迭代次数。当我尝试将数组中的单词与用户输入的单词进行比较时出现错误。不知道为什么。2)希望有人能解释迭代二进制和递归二进制之间的区别。3)为什么需要这样做...

SearchString si = new SearchString();

程序如下...

import ...

public class SearchString
{
public static final String TO_STOP = "-1";
public static final int NOT_FOUND = -1;
public static final int MAX_SIZE = 15000;

public static int count1;
public static int count2;
public static int count3;


public int sequentialSearch(String[] wordsArray, String word2Search)
{
int low = 0;
int high = wordsArray.length - 1;
for (int i = low; i <= high; i++)
{
count1++;
if (wordsArray[i] == word2Search)
return i;
}
return NOT_FOUND;
} // end of sequentialSearch()

public int binarySearch(String[] wordsArray, String word2Search)
{
int low = 0;
int high = wordsArray.length - 1;
while (low <= high)
{
int mid = (low + high)/2;
count2++;
if (wordsArray[mid] > word2Search){
high = mid - 1;
} else if (wordsArray[mid] < word2Search){
low = mid + 1;
} else
return mid;
}
return NOT_FOUND;
} /


public int binarySearch2(String[] wordsArray, int low, int high, String word2Search){
if (low > high)
return NOT_FOUND;
int mid = (low + high)/2;
count3++;
if (wordsArray[mid] > word2Search){
return binarySearch2(wordsArray, low, mid-1, word2Search);
} else if (wordsArray[mid] < word2Search){
return binarySearch2(wordsArray, mid+1, high, word2Search);
} else
return mid;
}



public static void main(String[] args) throws IOException
{
Scanner keyboard = new Scanner(System.in);

boolean wantToContinue = true;

Scanner stringsFile = new Scanner (new File("sortedStrings.txt"));//.useDelimiter(",\\s*");
List<String> words = new ArrayList<String>();

String token1 = "";

(stringsFile.hasNext())
{ token1 = stringsFile.next();
words.add(token1);
}
stringsFile.close();
String[] wordsArray = words.toArray(new String[0]);

System.out.println(Arrays.toString(wordsArray));

SearchString si = new SearchString();

do {
System.out.print("Type a word to search or -1 to stop: ");
String word2Search = keyboard.nextLine();
if (word2Search.equals(TO_STOP)){
wantToContinue = false;
} else {
count1 = count2 = count3 = 0;
int index;

index = si.sequentialSearch(wordsArray, word2Search);
if (index == NOT_FOUND)
System.out.println("sequentialSearch() : " + word2Search + " is not found (comparison=" + count1 + ").");
else
System.out.println("sequentialSearch() : " + word2Search + " is found in [" + index + "] (comparison=" + count1 + ").");

index = si.binarySearch(wordsArray, word2Search);
if (index == NOT_FOUND)
System.out.println("iterative binarySearch(): " + word2Search + " is not found (comparison=" + count2 + ").");
else
System.out.println("iterative binarySearch(): " + word2Search + " is found in [" + index + "] (comparison=" + count2 + ").");

index = si.binarySearch2(wordsArray, 0, wordsArray.length-1, word2Search);
if (index == NOT_FOUND)
System.out.println("recursive binarySearch(): " + word2Search + " is not found (comparison=" + count3 + ").");
else
System.out.println("recursive binarySearch(): " + word2Search + " is found in [" + index + "] (comparison=" + count3 + ").");
}
} while (wantToContinue);

}

}

最佳答案

您无法比较String== (或 >< )。你需要使用 String.compareTo

关于java - 比较字符串与数组字符串以及二分查找,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39562296/

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