java - Camel : xsl transformation doesn't indent xml

Question

我已经开始使用 Camel 进行 spring boot 并使用 xsl 进行新项目。我有以下示例:

students.xml

<?xml version="1.0" encoding="utf-8"?>
<class>
   <student rollno="393">
      <firstname>Dinkar</firstname>
      <lastname>Kad</lastname>
      <nickname>Dinkar</nickname>
      <marks>85</marks>
   </student>
   <student rollno="493">
      <firstname>Vaneet</firstname>
      <lastname>Gupta</lastname>
      <nickname>Vinni</nickname>
      <marks>95</marks>
   </student>
   <student rollno="593">
      <firstname>Jasvir</firstname>
      <lastname>Singh</lastname>
      <nickname>Jazz</nickname>
      <marks>90</marks>
   </student>
</class>

使用以下 xsl 进行转换(忽略注释；xsl 新手):

学生.xsl

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    version="1.0">
    <xsl:output method="xml" indent="yes" />

    <xsl:template match="*"><!-- matches any node -->
        <xsl:copy><!-- copies the current node and namespace nodes,NOT CHILD OR ATTRIBUTE NODES -->
            <xsl:apply-templates select="student" /><!-- applies template to students elements -->
        </xsl:copy>
    </xsl:template>

    <xsl:template match="student">
        <xsl:element name="person"><!-- renames element to person -->
            <xsl:attribute name="id-num"><!--  applies an attribute to new element called id-num -->
                <xsl:value-of select="@rollno" /><!-- copies value of student eles rollno attribute -->
            </xsl:attribute>
            <xsl:apply-templates select="lastname" /><!-- applies template to lastname child nodes -->
            <xsl:apply-templates select="marks" /><!-- applies template to marks child nodes -->
        </xsl:element>
    </xsl:template>

    <xsl:template match="lastname">
        <xsl:element name="student-surname">
            <xsl:attribute name="nick-name">
                 <xsl:value-of select="../nickname" /><!-- moves up a level in xml tree and copies value from nickname element -->
            </xsl:attribute>
            <xsl:value-of select="." /><!-- copies text value of current node -->
        </xsl:element>
    </xsl:template>

    <xsl:template match="marks">
        <xsl:element name="grade">
            <xsl:value-of select="." />
        </xsl:element>
    </xsl:template>
</xsl:stylesheet>

我通过 Camel 执行此转换。路由配置如下(camel spring boot starter，版本2.17.3):

SampleCamelRouter.java

@Component
public class SampleCamelRouter extends RouteBuilder {

    /* (non-Javadoc)
     * @see org.apache.camel.builder.RouteBuilder#configure()
     */
    @Override
    public void configure() throws Exception {
        // TODO Auto-generated method stub
        from("file:src/main/resources/input/?fileName=students.xml&noop=true")
            .to("xslt:./transforms/students.xsl")
            .to("file:target/messages/?fileName=studentsout.xml");
    }

}

每当我运行应用程序时，都会发生关于创建新元素、删除其他元素、复制值等的转换。但尽管 xsl:output 行位于文件开头附近，但它并没有缩进。我还尝试在之前的运行中添加 xsl:strip-space 标记，它不会影响输出。运行转换时得到的结果:

students-output.xml

<?xml version="1.0" encoding="UTF-8"?><class>
<person id-num="393">
<student-surname nick-name="Dinkar">Kad</student-surname>
<grade>85</grade>
</person>
<person id-num="493">
<student-surname nick-name="Vinni">Gupta</student-surname>
<grade>95</grade>
</person>
<person id-num="593">
<student-surname nick-name="Jazz">Singh</student-surname>
<grade>90</grade>
</person>
</class>

我有什么遗漏的吗？模板是否会干扰缩进？

Answer 1

尝试改变:

<xsl:output method="xml" indent="yes" />

至:

<xsl:output method="xml" indent="yes" xalan:indent-amount="2" xmlns:xalan="http://xml.apache.org/xalan"/>