java - if else 语句赋值

Question

编辑:我重新编写了一些代码，但如果用户输入的时间少于一周，我仍然无法让它计算费率。我的新代码如下。如有任何帮助，我们将不胜感激。我必须编写一段代码来模拟给出汽车租赁报价，其中用户输入颜色、租赁天数，并在两种类型的车辆之间进行选择。每种类型有两种费率，每周一次，每天一次。然后我必须找到最佳速率并将其输出。当我在下面的代码中输入白色、经济和 4 时，它不会输出任何内容。我认为我的汇率错误持续了不到一周，但我不知道如何修复它。

 import java.util.Scanner;
public class lab3
 {


    public static final double ECONOMY_DAILY = 25.5;
    public static final double FULL_DAILY = 39.4;
    public static final double ECONOMY_WEEKLY = 120.5;
    public static final double FULL_WEEKLY = 216.25;
    public static void main (String[] args)
     {
        Scanner Keyboard = new Scanner(System.in);

        System.out.println("Enter the color of the vehicle:");
            //string the next input as color
        String color = Keyboard.next();

        System.out.println ("Economy or Full:");
            // string the type of the vehicle
        String Type = Keyboard.next();
            // to get the character value to uppercase for the switch statement
        char FirstTypeLetter = Type.toUpperCase()
        .charAt(0); 
        System.out.println("For how many days?");
            //set days as the next integer entered and calculate the amount of weeks and daysleftover using the / and % operators
        int days = Keyboard.nextInt();
        int weeks = days/7;
        int daysLeftOver = days%7;
        double weeksRounded = ((days/7)*100)/100;

    double rate1,rate2,rate3;

        // create a switch using the variable defined earlier
    switch (FirstTypeLetter) 
    {
            // if the Type entry starts with an e
            case 'F':
                // calculate the 3 rates for full size using the full size constants (could have put this code anywhere above the next if statement.)
            rate1 = weeksRounded * FULL_WEEKLY;
            rate2 = (weeks * FULL_WEEKLY) + (days * FULL_DAILY);
           rate3 = (days * ECONOMY_DAILY);
           break;
        case 'E':
            // calculate all available rents for economy using the constants defined earlier
   rate1 = weeksRounded * ECONOMY_WEEKLY;
     rate2 = (weeks * ECONOMY_WEEKLY) + (days * ECONOMY_DAILY);
     rate3 = (days * ECONOMY_DAILY);

        break;
        default:
       System.out.println("Try Again!");
        rate1 = 0;
        rate2 = 0;
        rate3 = 0;
       }
            if ((rate1 < rate2) & (rate1 < rate3) & (rate1 != 0)) 
            {   
                    // print out the first rate as well as the color and type that the user entered
                System.out.printf("This is the best rate for a" + " " + color + " " + Type + " vehicle for" + " " + days + "days:" + "%.2f",rate1);
            }
                // if not, and if the second rate is cheapest
            if ((rate2 < rate1) & (rate2 < rate3) & (rate1 != 0))
            {
                    // print out the second rate as well as the color and type that the user entered
                System.out.printf("This is the best rate for a" + " " + color + " " + Type + " vehicle for" + " " + days + "days:" + "%.2f", rate2);
            }
                    // if the third rate is cheapest then print out that rate
            else if ((rate3 < rate2) & (rate3 < rate1) & (rate3 != 0)) 

                System.out.printf("This is the best rate for a" + " " + color + " " + Type + " vehicle for" + " " + days + "days:" + "%.2f", rate3);
            }



   }

Answer 1

您需要考虑一些事情:

• 案例 F 和案例 E 之间缺少一个中断，这意味着费率 F 将替换为费率 E
• 比较费率的逻辑(第 53 行)不应仅应用于情况“E”，它应该在 switch 语句之外。
• 没有选项可以通过每日选项来验证费率(如果天数少于 7 天，则会超出周期(请检查计算“费率 1”的逻辑)。
• 您应该使用调试器来验证分配给程序的值(使用 JUnit 或 testNG 进行自动化单元测试将变得很方便)
• 如果您没有调试器，System.out.println() 可用于验证分配的值，只需记住将它们取出即可。