python - 计算 "Rock, Paper, Scissors"中的平均值

Question

昨晚我在想“石头剪刀布”连续 10 次得到相同结果的概率。我想出了如何做到这一点并完成了该任务，但后来我想挑战一下自己，所以我想调整该程序，使其运行初始程序多次(10,000)，然后输出平均结果，我将其希望接近连续 10 次获得相同结果的概率。请注意，我没有考虑战术，只是两个玩家随机选择 r、p 或 s。

def rps():

   num=0 # num is the number of times i want the programme to run while roll<10: 
   total=0 # this should be close to 3^10 * 10000, its the result of all the tries added together 

   while num <10001:
      tries=0 # this is how many times the programme has tried to get p1=p2
      roll=0 # this is the amount of times it has counted p1=p2 (it gets re-set everytime it reaches 10)
      import random
      while roll <10:
         p1=random.randint(1,3)
         p2=random.randint(1,3)
         if p1==p2:
            roll=roll+1
         else:
            tries=tries + 1
            roll=0    
            num=num+1
         if roll==10:
            total=total+roll
            roll=0
      if num==10000:
         print (num)
         print (total/num)
rps()

Answer 1

程序有很多问题，这一次，第二个for循环没有任何用处，我知道你正在使用第二个for循环来重置计数器，如果连续滚动的数量达到10 ，但你已经在这里这样做了

if roll==10:
    total=total+roll
    roll=0

通过设置 roll=0，您将重置它。另外，最后一个 if 条件增加了复杂性，

if num==10000:
         print (num)
         print (total/num)

除此之外，您还可以像这样在循环外打印平均值

if roll==10:
    total=total+roll
    roll=0
print (total/10000) #this being outside the while loop

还有一件事，仅当 roll1 != roll2 时才递增 num，这会增加循环必须运行的次数修改后程序是这样的

import random
def rps():
    num=0 #num is the number of times i want the programme to run while roll<10:
    total=0 #this should be close to 3^10 * 10000, its the result of all the tries added together
    roll = 0
    while num <10001:
        tries=0 #this is how many times the programme has tried to get p1=p2
        p1=random.randint(1,3)
        p2=random.randint(1,3)
        if p1==p2:
            roll = roll+1
        else:
            tries = tries + 1
            roll = 0
        if roll==10:
            print(roll)
            total += roll
            roll=0
        num = num + 1
    print (total/10000)
    print(tries)
rps()

答案是 0，我猜你连续得到 10 的可能性很小。