arrays - 加入 m 大小数组的前 n 个元素

Question

给定:$array = ("a0", "a1", "b0", "b1")

我如何加入仅 array[0] & array[1];这样:

$a = "a0a1"
# as if: >$a = $a[0]$a[1]

同样，
得到:$b = "b0b1"

Answer 1

您可以选择数组中的元素，然后使用-join 运算符:

$array = ("a0", "a1", "b0", "b1")
$a = $array[0..1] -join ''
$b = $array[2..3] -join ''

您可以使用逗号来选择不连续的元素。

$array = ("a0", "a1", "b0", "b1")
$c = $array[0,1,3] -join ''

如果你想要加入的元素有一些标准，你可以将数组分组然后加入组。

# Joins all elements that start with the same character.
$array = ("a0", "a1", "b0", "b1")
$a = $array| group {$_[0]}| foreach {$_.group -join ''}