java - 如何在spring中使用参数进行Rest Api调用

Question

我正在我的 Spring 项目中进行 REST API 调用。网址是:https://testinfo.com/user-api/rest/userinfo?uploadStartTime=1476882000&uploadEndTime=1476907200

这是我的代码:

public String getUserData(String uplaodStartTime,String uplaodEndTime) throws IOException{
        String user_url = https://testinfo.com/user-api/rest/userinfo
        String url = user_url + "?" + "uploadStartTime" + "=" +uplaodStartTime + "&"
                + "uploadEndTime" + "=" + uplaodEndTime;

        URL obj = new URL(url);
        HttpURLConnection con = (HttpURLConnection) obj.openConnection();
        con.setRequestMethod("GET");
        int responseCode = con.getResponseCode();       
        BufferedReader in = new BufferedReader(new InputStreamReader(con.getInputStream()));
        String inputLine;
        StringBuffer response = new StringBuffer();
        while ((inputLine = in.readLine()) != null) {
            response.append(inputLine);
        }
        in.close();
        return response.toString();

    }

有没有最好的方法可以在不硬编码 url 参数的情况下进行 REST API 调用？

Answer 1

使用 RestTemplate 怎么样？

final String uri = "http://localhost:8080/project/test";

RestTemplate rt = new RestTemplate();
String result = rt.getForObject(uri, String.class);

System.out.println(result);

如果有任何参数，则使用映射对象。

final String uri = "http://localhost:8080/project/test";

RestTemplate rt = new RestTemplate();

AnyVO any = new AnyVO(1, "Adam", "010-1234-1234", "test@email.com");
AnyVO result = rt.postForObject( uri, any, AnyVO.class);

System.out.println(result);