Python YAML 转储指针引用

Question

这个问题已经有答案了:

Avoid references in PyYAML (2 个回答)

已关闭 5 年前。

我正在尝试使用几个组件模板构建 YAML 文档。我正在加载它们，构建一个 Python 对象，然后尝试将它们转储(最终转储到文件中，但此示例只是打印)。正如您在下面看到的，它打印引用和指针，而不是我期望的字符串数据。我做错了什么(或没有做什么)？

这是我用来演示我的问题的示例:

import yaml

main_template = yaml.load('organization: main')

sub_template = yaml.load('''
division: development
other:
  data:
  - for: users
''')

users = [ 'alice', 'bob', 'kim' ]

all_user_data = dict(main_template)

user_list = []

for user in users:
    tmp = dict(sub_template)
    tmp['name'] = user
    user_list.append(tmp)

all_user_data['users'] = user_list
print(yaml.dump(all_user_data, default_flow_style=False))

这会产生:

organization: main
users:
- division: development
  name: alice
  other: &id001
    data:
    - for: users
- division: development
  name: bob
  other: *id001
- division: development
  name: kim
  other: *id001

我期待这样的输出:

organization: main
users:
- division: development
  name: alice
  other:
    data:
    - for: users
- division: development
  name: bob
  other:
    data:
    - for: users
- division: development
  name: kim
  other:
    data:
    - for: users

Answer 1

正如 Anthon 在 Avoid references in PyYAML 中所建议的那样，你可以这样做

yaml.Dumper.ignore_aliases = lambda *args : True

那么，

print(yaml.dump(all_user_data, default_flow_style=False))

产量

organization: main
users:
- division: development
  name: alice
  other:
    data:
    - for: users
- division: development
  name: bob
  other:
    data:
    - for: users
- division: development
  name: kim
  other:
    data:
    - for: users

我不知道为什么会这样。感谢安东。

奥利弗