python - 为什么有时会打印 "Correct!"两次并且不接受输入？

Question

'''我正在编写“刽子手游戏”的代码。但它打印的是“正确!”两次了还是不明白为什么...请告诉问题出在哪里'''

import random

def rand_word():

    fp=open("30.txt","r")
    list=fp.readlines()
    random_word=random.choice(list)
    return random_word
    fp.close()

def game(list):

    done=len(list)
    correct=0
    while correct!=done:
        letter=input(("Guess a letter: "))
        for i in range(done):
            if letter==list[i]:
                print("Correct!") #this line is unexpected being printed two times sometimes
                correct+=1          

    print("The word was {}".format(str(list)))

if __name__=="__main__":

    random_word=rand_word()
    list=list(random_word.lower())
    list.remove(list[len(list)-1])
    print(list)
    print("Welcome to Hangman Game!!")
    game(list)

Answer 1

当某个字母出现两次时就会发生这种情况。一个快速解决方法是添加一个标志来查看您是否已经找到该信件，如下所示:

while correct!=done:
    letter=input(("Guess a letter: "))
    found = False
    for i in range(done):
        if letter==list[i]:
            if not found:
                print("Correct!") #this line is unexpected being printed two times sometimes
                found = True
            correct+=1