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java - 如何摆脱 "has leaked window"?

转载 作者:行者123 更新时间:2023-12-01 09:15:07 25 4
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我已经通过谷歌查看了,但我找到的所有答案都与我的问题无关......

这是我的错误日志

Activity com.fittingroom.newtimezone.view.ActivityAcceptNotAccept has leaked window com.android.internal.policy.PhoneWindow$DecorView{57b68a6 V.ED..... R......D 0,0-324,534} that was originally added here
at android.view.ViewRootImpl.<init>(ViewRootImpl.java:565)
at android.view.WindowManagerGlobal.addView(WindowManagerGlobal.java:326)
at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:91)
at android.app.Dialog.show(Dialog.java:350)
at com.fittingroom.newtimezone.view.ActivityAcceptNotAccept.openProgress(ActivityAcceptNotAccept.java:125)
at com.fittingroom.newtimezone.presenters.PresenterActivityAcceptNotAccept.openProgress(PresenterActivityAcceptNotAccept.java:125)
at com.fittingroom.newtimezone.presenters.PresenterActivityAcceptNotAccept.access$000(PresenterActivityAcceptNotAccept.java:16)
at com.fittingroom.newtimezone.presenters.PresenterActivityAcceptNotAccept$1.onPreExecute(PresenterActivityAcceptNotAccept.java:35)
at android.os.AsyncTask.executeOnExecutor(AsyncTask.java:604)
at android.os.AsyncTask.execute(AsyncTask.java:551)
at com.fittingroom.newtimezone.presenters.PresenterActivityAcceptNotAccept.setCroppedPreviewImage(PresenterActivityAcceptNotAccept.java:51)
at com.fittingroom.newtimezone.view.ActivityAcceptNotAccept.accept(ActivityAcceptNotAccept.java:63)
at java.lang.reflect.Method.invoke(Native Method)
at android.view.View$DeclaredOnClickListener.onClick(View.java:4735)
at android.view.View.performClick(View.java:5697)
at android.view.View$PerformClick.run(View.java:22526)
at android.os.Handler.handleCallback(Handler.java:739)
at android.os.Handler.dispatchMessage(Handler.java:95)
at android.os.Looper.loop(Looper.java:158)
at android.app.ActivityThread.main(ActivityThread.java:7224)
at java.lang.reflect.Method.invoke(Native Method)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1230)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1120)

我正在做的事情,我只是创建进度对话框并在 assynk 任务的控制下,并且在 onPreExecute() 对话框中打开,因此在 onPostExecute() 对话框中关闭...

这是我的代码

public final class ActivityAcceptNotAccept extends Activity implements IActivityAcceptNotAccept {

private Dialog progressDialog;

@Override
protected void onCreate(Bundle savedInstanceState) {
requestWindowFeature(Window.FEATURE_NO_TITLE);
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_accept_not_accept);

...///

presenter.initView();


}

...///

@Override
public void initView() {
progressDialog = UtilClass.getDialog(ActivityAcceptNotAccept.this, getString(R.string.loading));
}

public final void accept(View view) {
switch (count) {
case firstClick:
presenter.setCroppedPreviewImage();
break;
case secondClick:
presenter.setResultOkAndFinishActivity();
break;
}
}

@Override
public void setDisplaySize() {
UtilClass.setDisplaySize(getWindowManager().getDefaultDisplay(), getWindow(), 95, 95);
}

@Override
public void openProgress() {
if (progressDialog != null) {
progressDialog.show();
}
}

@Override
public void closeProgress() {
if (progressDialog != null) {
progressDialog.cancel();
progressDialog = null;
}
}
}

有一种方法可以为我提供Dialog实例

public abstract class UtilClass {

public static Dialog getDialog(Context context, String text) {
final Dialog progressDialog = new Dialog(context);
progressDialog.setContentView(R.layout.dialog);
progressDialog.setCanceledOnTouchOutside(false);

final Window window = progressDialog.getWindow();
if (window != null) {
window.setBackgroundDrawableResource(android.R.color.transparent);
}else {
Logger.logError("window == null", new NullPointerException(), context);
}

final TextView msg = (TextView) progressDialog.findViewById(R.id.id_tv_loadingmsg);
msg.setText(text);

return progressDialog;
}

据我所知,没有什么特别的,只是创建对话框,显示它并最终关闭它,就是这样......

为什么我会收到此错误?

我做错了什么?

编辑

AsynkTask

public void setCroppedPreviewImage() {
new AsyncTask<Void, Void, byte[]>() {
@Override
protected void onPreExecute() {
super.onPreExecute();
openProgress();
}

@Override
protected byte[] doInBackground(Void... voids) {
final String path = model.getImageFilePath();
final Bitmap croppedBitmap = getCroppedBitmapFromPath(path);
return getByteArrayFromBitmap(croppedBitmap);
}

@Override
protected void onPostExecute(byte[] result) {
super.onPostExecute(result);
closeProgress();
iActivityAcceptNotAccept.setPreviewImage(result);
}
}.execute();
}

最佳答案

实际上,在我的例子中,原因不是正在进行的对话框。我试图删除进度并揭开真正的原因。这是由于位图解码过程中的 OOM...但我不知道为什么我收到错误日志,其中在 progressdialog 中说明了这个原因。

最终我的位图太大了,我不得不缩小它

我是这样完成的(如果有人有同样的问题)

final BitmapFactory.Options options = new BitmapFactory.Options();
options.inSampleSize = 2;
final Bitmap bitmap = BitmapFactory.decodeFile(photo.getAbsolutePath(), options);

这意味着我将位图大小缩小了 2 倍,现在应用程序可以完美运行!

关于java - 如何摆脱 "has leaked window"?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40609082/

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