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python - 在我的井字棋游戏中,我应该在哪里加入没有人获胜的事实

转载 作者:行者123 更新时间:2023-12-01 09:15:01 24 4
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我是编码新手,最近开始学习Python。我的第一个挑战是制作一款井字棋游戏。以下是我的游戏代码,除了没有获胜者(即游戏平局)外,一切正常;我想显示没有人赢得了比赛。我尝试在不同的地方合并else。但是,他们没有帮助。这是我的代码。

  # a dictionary to display the grid
grid = {
'1':'1', '2':'2', '3':'3',
'4':'4', '5':'5', '6':'6',
'7':'7', '8':'8', '9':'9'
}
# a list to store the values that has already been entered
used_places = []

# players and their symbols
player_1 = 'x'
player_2 = 'o'

# to store result
result = None

def grid_display():
#this function displays the grid
print('\n\n')
print(grid['1'], '\t|\t', grid['2'], '\t|\t', grid['3'])
print(''.rjust(19,'*'))
print(grid['4'], '\t|\t', grid['5'], '\t|\t', grid['6'])
print(''.rjust(19, '*'))
print(grid['7'], '\t|\t', grid['8'], '\t|\t', grid['9'])

def win_the_game():
# this function checks for result and returns true or false
if(
(grid['1'] == grid['2'] == grid['3']) or (grid['4'] == grid['5'] == grid['6']) or
(grid['7'] == grid['8'] == grid['9']) or (grid['1'] == grid['4'] == grid['7']) or
(grid['2'] == grid['5'] == grid['8']) or (grid['3'] == grid['6'] == grid['9']) or
(grid['1'] == grid['5'] == grid['9']) or (grid['3'] == grid['5'] == grid['7'])
):
return True
else:
return False

def taking_turns(turn):
#this function asks user for input
print("its turn of ", turn)
choice = input("enter your choice")
while not (choice.isdecimal() and choice in grid and (choice not in used_places)):
# taking proper input by checkin it with already entered numbers
# and if it is a number
# and if number is in between 1 and 9
choice = input("\nenter your choice properly:")

player_move(choice, turn)

def player_move(move, assign):
# this function fills the entered numbers into used_places list
# and replaces numbers in grid with user input
used_places.append(move)
grid[move] = assign

print("player 1 : 'X'")
print("player 2 : 'O'")

for i in range(0,10): # loops 9 times to play the game
if i % 2 == 0: # giving turns. if i is even, player 1 gets turn and odd, player 2
grid_display() # displaying complete grid
turn = player_1 # to display whose turn it is; refer the function
taking_turns(turn)
if win_the_game() == True: # if the called function returns true in this 'if'
result = turn # player 1 wins
break
else:
grid_display() # same code as above
turn = player_2
taking_turns(turn)

if win_the_game() == True:
result = turn
break

print('\n\n',result, "won the game!!") # printing result

最佳答案

不要设置 result = None,而是设置 result = 'Nobody'。

从你的逻辑来看,你只有在有人获胜时才设置结果,这会将默认结果留给任何人。

--编辑--

抱歉,我有点得意忘形,重写了你的游戏逻辑来证明我的解决方案。接受或保留它,但它现在工作得很好,也许您可​​以使用它作为示例来修复您自己的问题。

import os

# a dictionary to display the grid
grid = {
'1':'1', '2':'2', '3':'3',
'4':'4', '5':'5', '6':'6',
'7':'7', '8':'8', '9':'9'
}
# a list to store the values that are available
places = ['1','2','3','4','5','6','7','8','9']

# to store result
result = 'Nobody'

# starting player
turn = 'O'

# display a game grid
def grid_display():
os.system('cls' if os.name == 'nt' else 'clear')
#this function displays the grid
print
print(grid['1'], '|', grid['2'], '|', grid['3'])
print(''.rjust(25,'*'))
print(grid['4'], '|', grid['5'], '|', grid['6'])
print(''.rjust(25, '*'))
print(grid['7'], '|', grid['8'], '|', grid['9'])

# check to see if anyone has won or are we out of moves
def win_the_game():
# this function checks for result and returns true or false
if(
(grid['1'] == grid['2'] == grid['3']) or (grid['4'] == grid['5'] == grid['6']) or
(grid['7'] == grid['8'] == grid['9']) or (grid['1'] == grid['4'] == grid['7']) or
(grid['2'] == grid['5'] == grid['8']) or (grid['3'] == grid['6'] == grid['9']) or
(grid['1'] == grid['5'] == grid['9']) or (grid['3'] == grid['5'] == grid['7'])
):
return True

# checks if there are any moves left
elif not places:
return False

else:
return False

# input / grid update function
def taking_turns():
# this function asks user for input
# use RAW_INPUT to make it a string
print
print map(str, places)
choice = raw_input("\nEnter "+turn+"'s choice: ")

if choice in places:
# this removes the number from the available list
# and replaces numbers in grid with user input
places.remove(choice)
grid[choice] = turn


# Logic loop
while places:
grid_display() # always display the grid
if turn == "O": # giving turns.
turn = 'X'
taking_turns()
if win_the_game() == True: # if the called function returns true in this 'if'
result = turn # player 1 wins
grid_display() # Winners GRID
break
else:
turn = 'O'
taking_turns()
if win_the_game() == True:
result = turn
grid_display() # Winners GRID
break

# results
print
print(result, "won the game!!") # printing result
print

关于python - 在我的井字棋游戏中,我应该在哪里加入没有人获胜的事实,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51348009/

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