java - 如何在我的代码中集成循环

Question

我是 Java 新手。我的程序首先从用户那里获取有关其汽车的输入，然后显示结果。我需要将我的“Rövarspråk”集成到代码中，但我不太确定如何集成。如果用户拥有“Saab”或“Volvo”，则“rövarspråk”循环应更改用户的“字符串名称”。如果有不清楚的地方，请告诉我，我会尽力解释得更好。

提前致谢。

public static void main(String[] args) {
    String lookSaab;

    String consonantsx;
    String input;
    String slang;
    String add;
    // String
    int length;
    // int
    Scanner skriv;
    // Scanner

    String reg;
    String year;
    String brand;
    String name;
    String car;
    String when;
    String small;
    String medium;
    String big;
    // String 
    int mod;
    int randomNumber;
    int quota;
    int denominator;
    // int







    reg = JOptionPane.showInputDialog("Ange registreringsnummer"); // Input plate number of your car
    year = JOptionPane.showInputDialog("Ange årsmodell"); // Input model year of the car
    mod = Integer.parseInt(year); 
    brand = JOptionPane.showInputDialog("Ange bilmärke"); //Input car brand
    name = JOptionPane.showInputDialog("Ange ägare "
                                           + "(för - och efternamn)"); //Input owner of the car first name + last name
    car = brand + reg;
    Date date = new Date();
    java.text.SimpleDateFormat sdf = new java.text.SimpleDateFormat("EEE MMM dd");
    when = sdf.format(date);
    denominator = 1500;
    randomNumber = 1500 + (int)(Math.random() * ((40000 - 1500) + 1));
    quota = randomNumber / denominator;

    small = "Liten service"; 
    medium = "Medium service";
    big = "Stor service";
    if (randomNumber <= 8000){
        JOptionPane.showMessageDialog(null, small, "Typ av service", 1);
    } else if ( randomNumber <= 20000){ 
        JOptionPane.showMessageDialog(null, medium, "Typ av service", 1);
    } else {
        JOptionPane.showMessageDialog(null, big, "Typ av service", 1);
    }

    String resultat = "Bil: " + car + "\n" 
                      + "Årsmodell: " + mod + "\n"  
                      + "Ägare: " + name + "\n"  
                      + "Mästarställning: " + randomNumber + "\n"  
                      + "Inlämnad: " + when + "\n"  
                      + "Klar om: " + quota + " dagar";
    JOptionPane.showMessageDialog(null, resultat, "Resulat", 1);

    lookSaab = "Saab";

    if (brand.equals(lookSaab)){

    }

  /* Rövarspråket */



    consonantsx = "bBcCdDeEfFgGhHjJkKlLmMnNpPqQrRsStTvVwWxXzZ"; //Saves all consonants to string
char consonants[] = consonantsx.toCharArray();  //String to charr

System.out.println("Mata in en mening");
skriv = new Scanner(System.in);
input = skriv.nextLine();   //Saves the input
length = input.length();    //Length inc. space
char array[] = input.toCharArray(); // Input to a char array

slang = "";
    System.out.println("På rövarspråk:"); 
for(int i = 0; i<length; i++) {
        for(int x = 0; x<20; x++){
            if(array[i] == consonants[x])
            {
                add = array[i]+"o"+array[i];
                slang = slang + add;
                break;
            }
            else{
            }
        }
    }
    System.out.println(slang);
}
}

Answer 1

好的，正如前面提到的，一个好的开始是将您的 RoverSpraket 翻译器放入其自己的方法中:

public String rovarSpraket(String normalString) {

    final String consonantsx = "bBcCdDeEfFgGhHjJkKlLmMnNpPqQrRsStTvVwWxXzZ"; 
    char consonants[] = consonantsx.toCharArray(); // String to charr

    int length = normalString.length(); // Length inc. space
    char array[] = normalString.toCharArray(); // Input to a char array

    String slang = "";
    System.out.println("På rövarspråk:");
    for (int i = 0; i < length; i++) {
        for (int x = 0; x < 20; x++) {
            if (array[i] == consonants[x]) {
                String add = array[i] + "o" + array[i];
                slang = slang + add;
                break;
            } else {
            }
        }
    }
    return slang;
}

此方法采用“正常”字符串作为输入并返回它的 Rövarspråk 版本。

鉴于它现在可以在任何您想要的地方使用，例如:

 /i named my class "Goran" ;)
    Goran goran = new Goran(); //instatiate a class object

    String hello = "hello world";

    System.out.println(goran.rovarSpraket(hello)); //use class object method "roverSpraket"

这将在控制台上打印如下:

På rövarspråk:霍赫埃洛洛洛多德

剩下要做的唯一一件事就是在剩余的代码中使用它。我想你想要的是:

if (brand.equals("Saab") || brand.equals("Volvo")){
    name = rovarSpraket(name); //translate if brand is Saab or Volvo
}

以及调用该方法的工作示例(一种方法)

    public class Goran {

    public static void main(String[] args) {
        String brand;
        String name;

        //i named my class "Goran" ;)
        Goran goran = new Goran(); //instatiate a class object

        String hello = "hello world";

        System.out.println(goran.rovarSpraket(hello)); //use class object method "roverSpraket"

        brand = "Saab";
        name = "henry";

        if (brand.equals("Saab") || brand.equals("Volvo")){
            name = goran.rovarSpraket(name); //translate if brand is Saab or Volvo
        }

        System.out.println("new name is " + name);

    }

    public String rovarSpraket(String normalString) {

        final String consonantsx = "bBcCdDeEfFgGhHjJkKlLmMnNpPqQrRsStTvVwWxXzZ"; 
        char consonants[] = consonantsx.toCharArray(); // String to charr

        int length = normalString.length(); // Length inc. space
        char array[] = normalString.toCharArray(); // Input to a char array

        String slang = "";
        System.out.println("På rövarspråk:");
        for (int i = 0; i < length; i++) {
            for (int x = 0; x < 20; x++) {
                if (array[i] == consonants[x]) {
                    String add = array[i] + "o" + array[i];
                    slang = slang + add;
                    break;
                } else {
                }
            }
        }
        return slang;
    }
}

希望这对您有帮助^^