python - 将 Python 中的 '*' 字符读入新字符串时出现问题

Question

我正在尝试删除 SQL 文本中的多行 SQL 注释并执行其余语句。结果应该是一个新字符串，省略了所有多行 SQL 注释。

但是，当从 SELECT 语句中读取 '*' 字符时，会导致打印的输出字符串不正确。从逻辑上讲，这没有任何意义。想知道这个角色是否存在任何已知的 Python 错误？

#sql = "actual sql code goes here; \n /*comment #1*/ more sql code would go 
#here; \n more renditions of SQL code here; \n /*comment #2*/ SELECT*FROM 
#TABLE;"

sql = "SELECT* FROM TABLE a WHERE THIS TRUE"

sql_2 = ""
flag = True

try:

    for index, character in enumerate(sql):
        while (flag):
            if character != r'/' and sql[index + 1] != r'*':
                sql_2 += character
                flag = True
                break
            else:
                flag = False

        if (character == r'*' and sql[index + 1] == r'/'):
            flag = True

        elif (character == r'/' and sql[index - 1] == r'*'):
            flag = True

except IndexError:
    if character != r'/':
        sql_2 += character

print(sql_2)

预期输出:'SELECT* FROM TABLE a WHERE THIS TRUE'

实际输出:'SELEC'

Answer 1

import re

sql = "actual sql code goes here; \n /*comment #1*/ more sql code would go here; \n more renditions of SQL code here; \n /*comment #2*/ SELECT*FROM TABLE;"

re.sub(r'/[*].*[*]/', '', sql)

# Output =>
# 'actual sql code goes here; \n  more sql code would go here; \n more renditions of SQL code here; \n  SELECT*FROM TABLE;'