flutter - 类型 'Future' 不是类型 '() => void' 的子类型

Question

我试图在 Text 上打开一个 URL点击。为此，我正在使用 InkWell如下所示:

Row(
    mainAxisAlignment: MainAxisAlignment.spaceBetween,
    children: <Widget>[
       Text('${blogModel.timeElapsed} ago'),
       InkWell(
          child: Text('Read'),
          onTap: launchURL(blogModel.url),
       )
     ],
  )

使用这个我收到以下错误:

════════ Exception caught by widgets library ═══════════════════════════════════════════════════════
The following assertion was thrown building BlogTileWidget(dirty):
type 'Future<dynamic>' is not a subtype of type '() => void'

Either the assertion indicates an error in the framework itself, or we should provide substantially more information in this error message to help you determine and fix the underlying cause.
In either case, please report this assertion by filing a bug on GitHub:
  https://github.com/flutter/flutter/issues/new?template=BUG.md

Answer 1

您的 launchURL(blogModel.url)调用返回 Future , 和 onTap需要一个 void .

有 2 种解决方案可以解决此问题。

onTap: () => launchURL(blogModel.url),

onTap: () {
  launchURL(blogModel.url); // here you can also use async-await
}