java - 我如何找到循环中的第n项？ java

Question

这里是我编写的程序的快速浏览，以便为我的问题提供更好的示例。

循环代码

公共(public)无效方案1(int d){

     // first modification
    if (mark<=20){
          System.out.print("\nBecause mark under 20 mark stays as its original value. mark="+mark);
          return;
    }
    int total = mark;
    int finalMark=20;

    System.out.print("Scheme 1"+"\n");

// Loop
    for(int loopParameter = START_CONDITION;
    loopParameter <= d;loopParameter++){
        System.out.print("(" + loopParameter + ") " + total + "   ");
    total = total + constantDiffSch1;

      // second modification
     
     if (total < 40){
         System.out.print("\nThis work can be up to " + loopParameter);
         return;
      }
    
      // third modification
      if (total<=20){
         System.out.print("\nBecause mark drops below 20, mark stays as 20. final mark="+ finalMark);
        return;
      }
}   // End
System.out.print("\n\n");

}

这是我的程序输出

Please input mark: 64

Please input number of days to display: 10

Scheme 1

(0) 64 (1) 59 (2) 54 (3) 49 (4) 44

This work can be up to 4 days late before failing.

这就是输出应该是的

Please input mark: 64

Please input number of days to display: 10

Scheme 1

(0) 64 (1) 59 (2) 54 (3) 49 (4) 44 (5) 39 (6) 34 (7) 29 (8) 24

This work can be up to 4 days late before failing.

我必须显示作业迟到了多少天并计算迟到罚金(标记-5)我还必须显示作业失败所需的天数(失败之前的天数可能大于用户输入的天数 (d) )。不及格分数低于 40。

第二个示例(输出)

Please input mark: 64

Please input number of days to display: 2

Scheme 1

(0) 64 (1) 59 (2) 54

This work can be up to 4 days late before failing.

我几乎已经完成了我的代码，但这个问题正在减慢我的速度。

附注我是java新手

这是我的完整程序

逾期处罚类

public class LatePenalties {

    // attributes
    private int mark;

    private static final int constantDiffSch1 = -5;
    private static final double constantDiffSch2 = 0.9;
    private static final int START_CONDITION = 0;
    // constructors
    public LatePenalties(int m) {
        mark = m;

    }
    
    // methods
   
 public void scheme1(int d) {

         // first modification
        if (mark<=20){
              System.out.print("\nBecause mark under 20 mark stays as its original value. mark="+mark);
              return;
        }
        int total = mark;
        int finalMark=20;

        System.out.print("Scheme 1"+"\n");

    // Loop
        for(int loopParameter = START_CONDITION;
        loopParameter <= d;loopParameter++){
            System.out.print("(" + loopParameter + ") " + total + "   ");
        total = total + constantDiffSch1;

          // second modification
         
         if (total < 40){
             System.out.print("\nThis work can be up to " + loopParameter);
             return;
          }
        
          // third modification
          if (total<=20){
             System.out.print("\nBecause mark drops below 20, mark stays as 20. final mark="+ finalMark);
            return;
          }
    }   // End
    System.out.print("\n\n");
 }


 public void scheme2(int d) {
        double total = mark;

        System.out.print("\n\nScheme 2"+"\n");

    // Loop
        for(int loopParameter = START_CONDITION;
        loopParameter <= d;loopParameter++){
            System.out.print( "(" + loopParameter + ") " );
            System.out.printf("%.02f",total);
            System.out.print("   ");

        total = total * constantDiffSch2;
    }   // End
    System.out.print("\n");
 }
}         
 

主类

import java.util.Scanner;

public class LatePenaltiesUser {

    public static void main(String [] args) {
    // local variables
    Scanner input = new Scanner(System.in);
    LatePenalties latePen;
    int mark;
    int days;
    
    // input      
    do{
    System.out.print("Please input mark (between 0 and  100) --> ");
    mark  = input.nextInt();
    if  (( mark < 0 ) | (mark > 100 )){System.out.print("\n" + "Input value outside the range!!!" + "\n");}
    }while(( mark < 0 ) | (mark > 100 ));

    do{
    System.out.print("Please input number of days to display (between 0 and  20) --> ");
    days = input.nextInt();
    System.out.print("\n");
    if  (( days < 0 ) | (days > 20 )){System.out.print("Input value outside the range!!!"+ "\n");}
    }while(( days < 0 ) | (days > 20 ));

    // computation
    latePen = new LatePenalties(mark);
    latePen.scheme1(days);
    latePen.scheme2(days);

    }
}

我必须显示失败标记何时发生(小于 40)，但我必须在 20 处或达到天数时停止循环，正如我在示例中显示的预期内容。

Answer 1

当 total 小于 40 时，您可以使用 break 退出循环。您可以将 scheme1 方法更新为下面

public void scheme1(int d) {

        int total = mark;

        System.out.print("Scheme 1" + "\n");
        int days = 0;
        // Loop
        for (int loopParameter = START_CONDITION; loopParameter <= d; loopParameter++) {
            System.out.print("(" + loopParameter + ") " + total + "   ");
            total = total + constantDiffSch1;

            if(total < 40)
                break;
            days++;
        } // End
        if (total <= 40) {
            System.out.print("\nThis work can be up to " + days +" days late before failing.");
        }
        System.out.print("\n\n");
    }

Please input mark (between 0 and 100) --> 82 Please input number of days to display (between 0 and 20) --> 10

Scheme 1 (0) 82 (1) 77 (2) 72 (3) 67 (4) 62 (5) 57 (6) 52 (7) 47 (8) 42 This work can be up to 8 days late before failing.