sql - 行在自己的列中，具体取决于它们的值

Question

我有一个选择查询，目前产生以下结果:

Description   Code    Price
 Product 1     A        5
 Product 1     B        4
 Product 1     C        2

使用以下查询:

SELECT DISTINCT np.Description, p.promotionalCode, p.Price
FROM            Price AS p INNER JOIN
                         nProduct AS np ON p.nProduct = np.Id

我想制作以下内容:

Description  A  B  C
 Product 1   5  4  2

Answer 1

SELECT 
    np.Id, 
    np.Description, 
    MIN(Case promotionalCode WHEN 'A' THEN Price ELSE NULL END) AS 'A',
    MIN(Case promotionalCode WHEN 'B' THEN Price ELSE NULL END) AS 'B',
    MIN(Case promotionalCode WHEN 'C' THEN Price ELSE NULL END) AS 'C'
FROM 
    Price AS p 
INNER JOIN nProduct AS np ON p.nProduct = np.Id
GROUP BY 
    np.Id,
    np.Description

---

这是一个简单的测试示例:

DECLARE @temp TABLE (
    id INT,
    description varchar(50),
    promotionalCode char(1),
    Price smallmoney
)

INSERT INTO @temp
select 1, 'Product 1', 'A', 5
    union
SELECT 1, 'Product 1',  'B', 4
    union
SELECT 1, 'Product 1', 'C', 2



SELECT
    id,
    description,
    MIN(Case promotionalCode WHEN 'A' THEN Price ELSE NULL END) AS 'A',
    MIN(Case promotionalCode WHEN 'B' THEN Price ELSE NULL END) AS 'B',
    MIN(Case promotionalCode WHEN 'C' THEN Price ELSE NULL END) AS 'C'
FROM
     @temp
GROUP BY 
    id,
    description