regex - 如何编写以特定单词匹配开头并一直持续到遇到句点的正则表达式

Question

我试图编写一个正则表达式来匹配特定单词并继续匹配直到遇到句点。例如:

文本:

Which Have Never Won Two Races Other Than Maiden, Claiming, Or Starter Or Which Have Never Won Three Races Or Optional Claiming Price Of $25,000. Three Year Olds, 118 Lbs.; Older, 123 Lbs. Non-winners of $24,000 since March 9 Allowed 2 Lbs.

期望的匹配:

Which Have Never Won Two Races Other Than Maiden, Claiming, Or Starter Or Which Have Never Won Three Races Or Optional Claiming Price Of $25,000.

正则表达式:

(?<Match1>Which\s[a-zA-Z]*[.])

不幸的是，我提议的表达式捕获了所有文本，并且似乎延伸到最后一个句点而不是第一个句点。`

Answer 1

其实很简单。使用 [^.]* 匹配所有字符，但不包括下一个 . 并用 \b 边界包围您想要的单词。我将最后的 . 附加为 \. 假设您想将其包含在匹配的输出中。

(?<Match1>\bWhich\b[^.]*\.)