python - 触发 Jenkins 的命令不起作用

Question

我是Python新手，

下面是用于触发 Jenkins 项目的 python 脚本。

 '''subprocess for triggering jenkins'''
 print("Update Started 2.........subprocess for triggering jenkins.")
 #cmd2 = ['curl', c3]
 mycmd = r'start chrome/new-tab {}'.format(c3)

 n2=subprocess.Popen(mycmd, shell=True, stdin=subprocess.PIPE, stdout=subprocess.PIPE)

 #wait for the process to terminate
 #out, err = n2.communicate()
 #errcode = n2.returncode

 '''wait until trigger the jenkins'''
 print("Wait until trigger the jenkins..................")

 # Deadlock is happening here.
 n2.wait()
 print("Wait done.......................................")

它没有触发该项目，但是，当我在调试状态下尝试时 - 这个地方发生了死锁 n2.wait()

下面是脚本的日志:

Update Started 2.........subprocess for triggering jenkins.
Wait until trigger jenkins..................

更新 1:当我尝试修改时..

n2.wait(10) 

下面是控制台打印的数据。

Traceback (most recent call last):
  File "C:/Users/adevaraj/Desktop/Jenkins_CVS_Testing_Apr/CVS_LOG_Compare.py", line 189, in <module>
    n2.wait(10)
  File "C:\Program Files (x86)\Python36-32\lib\subprocess.py", line 1057, in wait
    raise TimeoutExpired(self.args, timeout)
subprocess.TimeoutExpired: Command 'start chrome/new-tab http://localhost:8080/job/P16G0804_GM_A2XX_PSS/build?token=A2XX' timed out after 10 seconds

更新 2:Url 正在从 Excel 工作表中获取(该代码未在此处发布)

更新3:

在此代码中，c3 是后端触发器的 url

谁能帮帮我。

Answer 1

我假设您想触发 Jenkins 构建。简单地使用 Jenkins REST API 怎么样。

import requests 
url = "http://localhost:8080/job/P16G0804_GM_A2XX_PSS/buildWithParameters? 
arg1=val1&arg2=val2"
response = requests.get(url)
print(response)

希望对您有帮助!