python - 显示嵌套模型的 InlineModelAdmin

Question

我有带有 OneToOneFields 的嵌套模型，并且希望在一个 ModelAdmin 中有一个 InlineModelAdmin 表单来指向嵌套模型...

models.py:

class User(models.Model):
    username = models.CharField(max_length=128)
    password = models.charField(max_length=128)

class IdentityProof(models.Model):
    user = models.OneToOneField(User, on_delete=models.PROTECT, related_name='proof')
    proof_identity = models.FileField(upload_to='uploads/%Y/%m/%d/')

class Company(models.Model):
    user = models.OneToOneField(User, on_delete=models.PROTECT, related_name='company')
    name = models.CharField(max_length=128)

class Person(models.Model):
    user = models.OneToOneField(User, on_delete=models.PROTECT, related_name='person')
    name = models.CharField(max_length=128)

admin.py:

class IdentityProofInline(admin.TabularInline):
    model = IdentityProof

@admin.register(Company)
class CompanyAdmin(admin.ModelAdmin):
    inlines = [IdentityProofInline]

@admin.register(Person)
class PersonAdmin(admin.ModelAdmin):
    inlines = [IdentityProofInline]

对于 CompanyAdmin 或 PersonAdmin，我想显示其用户的身份证明。我怎样才能做到这一点？

我尝试使用fk_name = 'user_proof或其他组合，但它不起作用......

谢谢。

Answer 1

如果没有外部包，这是不可能的。

请参阅Django Nested Inline和 Django Nested Admin