python - 对 datetime.datetime 二维数组进行排序

Question

我有以下二维数组，日期格式为 %Y-%m-%d %H:%M:%S :

[['second comment test', datetime.datetime(2018, 8, 22, 15, 49, 40), 's']
['this comment originated in service now', datetime.datetime(2018, 8, 22, 14, 45), 's']
['this is a longer description used for testing', datetime.datetime(2018, 8, 22, 14, 13, 49), 'z']]

我注意到，如果时间日志之一正好是一分钟，例如2018-08-22 14:45:00，这意味着它以 00 结尾，它不会记录秒数。那么如何按日期对这个数组进行排序呢？

Answer 1

假设您拥有的是一个列表，如@DietrichEpp所述，您可以简单地按以下方式对该数组进行排序:

list_ = [
    ['second comment test', datetime.datetime(2018, 8, 22, 15, 49, 40), 's'],
    ['this comment originated in service now', datetime.datetime(2018, 8, 22, 14, 45), 's'],
    ['this is a longer description used for testing', datetime.datetime(2018, 8, 22, 14, 13, 49), 'z'],]
list_.sort(key=lambda x: x[1])