python - 奥杜 10 : Getting a view like invoice _line_ids from Invoice module

Question

我正在扩展员工模块以列出员工从公司获得的所有设备。下面是我的 models.py :

# -*- coding: utf-8 -*-

from odoo import models, fields, api

class device_types(models.Model):
    _name = "device.types"
    name = fields.Char()

class device_names(models.Model):
    _name = "device.names"
    name = fields.Char()
    #devices_names = fields.Many2one('hr.employee')


class devices(models.Model):
    _name = "devices"

    #devices_types = fields.Many2one('device.types')
    devices_id = fields.Many2one('hr.employee')
    devices_types = fields.Char()
    devices_names = fields.Char()



    #employee_id = fields.Many2one('hr.employee')


class employee_devices(models.Model):
     _inherit = 'hr.employee'
     #devices_lines_ids = fields.One2many('devices','devices_id',string='Device Lines',readonly=True, states={'draft': [('readonly', False)]}, copy=True)
     devices_lines_ids = fields.One2many('devices','devices_id',string='Device Lines')
     #devices_names = fields.Many2one('devices')
     #devices_types = fields.Many2one('devices')
     devices_types = fields.One2many('devices','devices_types')
     devices_names = fields.One2many('devices.names')

和我的 view.xml :

<odoo>
  <data>
    <!-- explicit list view definition -->

    <record id="invoice_form" model="ir.ui.view">
    <field name="model">hr.employee</field>
    <field name="inherit_id" ref="hr.view_employee_form" />
    <field name="priority" eval="1"/>
    <field name="arch" type="xml"> 
        <xpath expr="//notebook//page[@name='hr_settings']" position="after">
         <page name="Devices" string="Devices" groups="hr.group_hr_user">
                                <group>
                                    <group string="Devices" name="devices_group">
                                        <field name="devices_lines_ids" nolabel="1" widget="one2many_list" mode="tree" >
                                         <tree string="Devices" editable="bottom">
                                           <field name="devices_types" />
                                              <field name="devices_names"/> 
                                         </tree> 
                                        </field>
                                    </group>
                                </group>
        </page>
       </xpath>
    </field>
</record>


  </data>
</odoo>

我能够实现这一目标:

但我希望在设备类型和设备名称列中有一个下拉菜单，能够创建新类型和名称。我尝试了不同的组合，正如您在 models.py 的评论中看到的那样。我怎样才能在我的 View 中获得下拉菜单？？？

简而言之，我想要这种类型的 View ，我可以在 TreeView 中编辑每一列，并且某些列具有下拉菜单:

Answer 1

已修复。我更新的modules.py:

# -*- coding: utf-8 -*-

from odoo import models, fields, api

class device_types(models.Model):
    _name = "device.types"
    name = fields.Char()

class device_names(models.Model):
    _name = "device.names"
    name = fields.Char()


class devices(models.Model):
    _name = "devices"
    employee_name = fields.Many2one('hr.employee')
    devices_names = fields.Many2one('device.names')
    devices_types = fields.Many2one('device.types')



class employee_devices(models.Model):
     _inherit = 'hr.employee'
     devices_lines_ids = fields.One2many('devices','employee_name',string='Device Lines',states={'draft': [('readonly', False)]}, copy=True)

和我的views.xml:

    <odoo>
    <data>
    <!-- explicit list view definition -->

    <record id="invoice_form" model="ir.ui.view">
      <field name="model">hr.employee</field>
      <field name="inherit_id" ref="hr.view_employee_form" />
      <field name="priority" eval="1"/>
      <field name="arch" type="xml">
        <xpath expr="//notebook//page[@name='hr_settings']" position="after">
          <page name="Devices" string="Devices" groups="hr.group_hr_user">
            <group>
                <field name="devices_lines_ids" nolabel="1" widget="one2many_list" mode="tree">
                  <tree string="Devices" editable="bottom">
                    <field name="devices_types" />
                    <field name="devices_names"/>
                  </tree>
                </field>
            </group>
          </page>
        </xpath>
      </field>
    </record>
  </data>
</odoo>