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python - int() 参数必须是字符串、类似字节的对象或数字,而不是 'QuerySet'

转载 作者:行者123 更新时间:2023-12-01 09:01:05 26 4
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我的工作地址为 this tutorial作为指导。他们的 SignupForm 与我的非常相似,但当我尝试添加多对多。 (这只是最终形成多种用户类型的第一步,因此在 MyUser 类上使用 is_xyz 类型 bool 值并不是一个长期解决方案):

models.py

class MyUser(AbstractBaseUser, PermissionsMixin):
email = models.EmailField(
verbose_name='email address',
max_length=255,
unique=True,
)

is_admin = models.BooleanField(default=False)
is_superuser = models.BooleanField(default=False)

objects = MyUserManager()

USERNAME_FIELD = 'email'
REQUIRED_FIELDS = []

def __str__(self):
return self.email

def has_perm(self, perm, obj=None):
# Does the user have a specific permission?
# Simplest possible answer: Yes, always
return True

def has_module_perms(self, app_label):
# "Does the user have permissions to view the app `app_label`?"
# Simplest possible answer: Yes, always
return True

@property
def is_staff(self):
return self.is_admin

class Meta:
db_table = 'users_myuser'
verbose_name = 'MyUser'


class ApplicationUser(models.Model):
user = models.OneToOneField(MyUser, on_delete=models.CASCADE)


class AdminUser(models.Model):
user = models.OneToOneField(MyUser, on_delete=models.CASCADE)
destination = models.ManyToManyField(Destination, blank=True)

forms.py

class GatekeeperPlusSuperCreationForm(forms.ModelForm):

password1 = CharField(label="Password", widget=PasswordInput)
password2 = CharField(label="Password confirmation", widget=PasswordInput)

class Meta:
model = get_user_model()
fields = ('email',)

destination = forms.ModelMultipleChoiceField(queryset=Destination.objects.all(), widget=forms.CheckboxSelectMultiple,
required=True)

def clean_password2(self):
password1 = self.cleaned_data.get("password1")
password2 = self.cleaned_data.get("password2")
if password1 and password2 and password1 != password2:
msg = "Passwords don't match"
raise forms.ValidationError("Password mismatch")
return password2

def save(self, commit=True):
user = super(GatekeeperPlusSuperCreationForm, self).save(commit=False)
user.set_password(self.cleaned_data["password1"])
user.is_admin = True
user.save()

admin_user = AdminUser.objects.create(user=user)
admin_user.destination.add(self.cleaned_data["destination"])

return admin_user

我在行上收到错误 admin_user.destination.add(self.cleaned_data["destination"])
。当我尝试 print(self.cleaned_data["destination"]) 时,它确实显示它是一个 QuerySet,但为什么呢?

如何从 destination = forms.ModelMultipleChoiceField(queryset=Destination.objects.all(), widget=forms.CheckboxSelectMultiple, required=True) 中获取值并将其保存为 ManyToManyField ?

最佳答案

因为destination允许您选择多个值,所以它不是单个对象,而是多个。

但是,您可以通过序列解包轻松解决此问题:

admin_user.destination.add(<b>*</b>self.cleaned_data["destination"])
# ^

因此,我们在参数前面放置了一个星号 (*)。这样,QuerySet 中的元素就会被解包,并作为单独的元素传递给 .add(..) 函数。

Note: after reading the article, it turns out that the authors used sequence unpacking as well.

请注意,Django 支持使用 save_m2m [Django-doc] 保存多对多关系。功能。

关于python - int() 参数必须是字符串、类似字节的对象或数字,而不是 'QuerySet',我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52451519/

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