java - 如何使用 scala 正确向亚马逊 sqs 队列发送消息？

Question

我见过这个common-aws on github如何使用它，这是他们的示例(仅适用于发件人，因为这就是我需要的):

import com.amazonaws.services.sqs.AmazonSQSAsyncClient 
import com.pellucid.wrap.sqs.AmazonSQSScalaClient
import com.mfglabs.commons.aws.sqs._

val sqs = new AmazonSQSScalaClient(new AmazonSQSAsyncClient(), ec)
val builder = SQSStreamBuilder(sqs)

val sender: Flow[String, SendMessageResult, Unit] =
  Flow[String].map { body =>
    val req = new SendMessageRequest()
    req.setMessageBody(body)
    req.setQueueUrl(queueUrl)
    req
  }
  .via(builder.sendMessageAsStream())

但是我遇到了一些错误，而且我不太理解这个例子，我需要的是创建一个接受案例类列表的函数，将列表中的每个列表序列化为 json 并将其发送到 sqs 队列...就是这样，这就是我到目前为止尝试过的:

val queueUrl = "the url to my queue"

//the objects here are of case class type ObjectUploadRequest
val listOfObjects = List(Obj1, Obj2, Obj3, Obj4, Obj5)

def pushListToSQS(listOfObjectsRequests: List[ObjectUploadRequest]): Future[SendMessageRequest] = {
  listOfObjectsRequests.map(objReq => {
    val ser = swrite(objReq)
    val sender: Flow[String, SendMessageResult, Unit] =
      Flow[String].map { body =>
        val req = new SendMessageRequest()
        req.setMessageBody(body)
        req.setQueueUrl(queueUrl)
        req
      }.via(builder.sendMessageAsStream())
  })
}

我收到此错误:

如果有人能提供帮助，我将不胜感激，谢谢

Answer 1

如果您不介意使用旧的 AWS Java SDK 及其同步 SQS 客户端，那么这对我有用:

import com.amazonaws.services.sqs.AmazonSQSClient
import com.amazonaws.services.sqs.model.SendMessageRequest  

val sqs = new AmazonSQSClient()

listOfObjects.foreach { obj =>
    val json = // convert obj to json

    sqs.sendMessage(new SendMessageRequest()
        .withQueueUrl("your queue url")
        .withMessageBody(json))
}