Java如何在条件为假时继续当前循环

Question

我遇到一个问题，每当输入验证不正确时，它就会跳出当前循环并继续执行下一个方法，任何人都可以帮助我，这样当条件为假时，它会重新请求相同的输入，直到满足条件。这是我的方法类的源代码

public class Student {
    public int gradePt;
    public int i;
    public int credSum = 0;
    public double gradeCredSum = 0;
    public double gpa;
    String [] moduleName;
    String [] moduleGrade;
    int [] moduleCred ;
    Module[] modules;

    public void createModules(){

        getModuleNo();

         modules = new Module[i];
         moduleName = new String[i];
         moduleGrade = new String[i];
         moduleCred = new int[i];

         getModule();
         getGrade();
         getCred();

    for (int j = 0; j < modules.length; j++) {


       modules[j] = new Module(moduleName[j],moduleCred[j],moduleGrade[j]);
       }
    }

    public void getModuleNo(){
        do{
     String input  = JOptionPane.showInputDialog(null,
             "How many modules did you take?","Input");
           int a  = Integer.parseInt(input);
           if (a<1 || a>8){
               JOptionPane.showMessageDialog(null, 
                       "Invalid input please enter a number greater than 0",
                       "Error",JOptionPane.ERROR_MESSAGE);
               break;
    }      i = a;  
        }while(i<1 || i>8);  

}
    public void getModule(){
        for (int i=0;i<moduleName.length;i++){
             String input = JOptionPane.showInputDialog(null,
                    "Enter the name of module #"+(i+1));
             moduleName[i] = input;
             if (input == ""){
                 JOptionPane.showMessageDialog(null,
                         "Invalid input, module name cannot be blank","Error",JOptionPane.ERROR_MESSAGE);
                 break;
       }
    }

    }
    public void getGrade(){
        for (int i=0;i<moduleGrade.length;i++){
            String input = JOptionPane.showInputDialog(null,
                    "Enter grade (A,B,C,D,F) for module #"+(i+1));
             moduleGrade[i] = input;
             if (!"A".equals(input) && !"B".equals(input) && !"C".equals(input) && !"D".equals(input) &&
                     !"F".equals(input) && !"a".equals(input) && !"b".equals(input) && input!="c" &&
                     !"d".equals(input) && !"f".equals(input)){
                 JOptionPane.showMessageDialog(null,
                         "Invalid input!"+"\n"+"Please enter A,B,C,D or F","Error",JOptionPane.ERROR_MESSAGE);
                 break;
             }
             moduleGrade[i] = input;
      }
    }
    public void getCred(){

        for (int i=0;i<moduleCred.length;i++){
            String input = JOptionPane.showInputDialog(null,
                    "Enter credit units for module #"+(i+1));
             moduleCred[i] = Integer.parseInt(input);
             if (moduleCred[i]<1 || moduleCred[i]>8){
                 JOptionPane.showMessageDialog(null,
                         "Invalid input!"+"\n"+"Please enter a number form 1 to 8","Error",JOptionPane.ERROR_MESSAGE);
                 break;
             }

        }
    }

Answer 1

这是一个常见的过程。您不断要求输入，每次都进行检查，直到输入有效。

伪代码:

repeat
  display("Please enter your input: ")
  input <- getInput()
until (isValid(input))